Answer:
A) g = 9.751 m/s², B) h = 2.573 10⁴ m
Explanation:
The angular velocity of a pendulum is
w = √ g / L
Angular velocity and frequency are related.
w = 2π f
f = 1 / 2π √ g / L
A) with the initial data we can look for the pendulum length
L = 1 /4π² g / f²
L = 1 /4π² 9,800 / 0.3204²
L = 2.4181 m
The length of the pendulum does not change, let's look for the value of g for the new location
g = 4π² f² L
g = 4π² 0.3196² 2.4181
g = 9.75096 m / s²
g = 9.751 m/s²
B) The value of the acceleration of gravity can be found with the law of universal gravitation
F = G m M /
²
And Newton's second law
W = m g
W = F
G m M /
² = mg
g = G M /
²
² = G M / g
Let's calculate
² = 6.67 10⁻¹¹ 5.98 10²⁴ /9.75096
R = √ 4.0905 10¹³ = √ 40.9053 10¹²
R = 6.395726 10⁶ m
The height above sea level is
h = R - [tex]R_{e}[/tex
h = (6.395726 -6.37) 10⁶
h = 0.0257256 106
h = 2.573 10⁴ m
The simplest answer would be "acceleration due to gravity."
The exact value of this acceleration changes depending on which planet your on (for example).
Answer:
was is carl sagan?
Explanation:
please forgive me if im wrong :(
Answer:
6 V
Explanation:
We can solve the problem by using Ohm's law:

where
V is the voltage in the circuit
R is the resistance
I is the current
In this problem, we know the current,
, and the resistance,
, therefore we can find the voltage in the circuit:

For purposes of completing our calculations, we're going to assume that
the experiment takes place on or near the surface of the Earth.
The acceleration of gravity on Earth is about 9.8 m/s², directed toward the
center of the planet. That means that the downward speed of a falling object
increases by 9.8 m/s for every second that it falls.
3 seconds after being dropped, a stone is falling at (3 x 9.8) = 29.4 m/s.
That's the vertical component of its velocity. The horizontal component is
the same as it was at the instant of the drop, provided there is no horizontal
force on the stone during its fall.