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Mamont248 [21]
3 years ago
13

A man has 60w bulbs and a 240w water heater in his apartment. If the bulbs and the water heater are switched on for four hours d

aily and the cost of electricity is N1.20 per KWh calculare his bill in 30 days
Physics
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer: N43.2

Explanation:

Given

Power consumption of bulb and water are 60\ W and 240\ W

If the Devices are on for four hours

Total power of devices 60+240=300\ W

Energy consumed for 4 hours is

\Rightarrow 300\times 4=1200 Wh\\\Rightarrow 1.2\ kWh

For 30 days it is 1.2\times 30=36\ kWh

Cost for 30 days 36\times 1.2=43.2\ N

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1. Una carga Q1 = + 12 μC se coloca a una distancia r = 0.024 m desde una carga Q2 = + 16 μC. a) Determina la magnitud de la fue
lyudmila [28]

Answer:

1. a. 3,000 N

b. Repulsión

2. 46.875 × 10⁶ N/C

3. a. 81,000 J

b. 6.75 × 10⁹ V

Explanation:

1. Los parámetros dados son;

Q₁ = +12 μC, Q₂ = +16 μC

La distancia entre las cargas, r = 0.024

La magnitud de la fuerza electrostática, F, entre cargas se da como sigue;

F = k \times \dfrac{Q_1 \cdot Q_2}{r^2}

Donde, k = constante de Coulomb = 9.0 × 10⁹ N · m² / C²

Por lo tanto, obtenemos;

F = 9.0 × 10⁹ × 12 × 10⁻⁶ × 16 × 10⁻⁶ / 0.024² = 3.000

La magnitud de la fuerza electrostática, entre las cargas, F = 3000 N

(b) Dado que tanto Q₁ como Q₂ son cargas positivas, y las cargas iguales se repelen entre sí, la fuerza es la repulsión.

2) La intensidad de un campo eléctrico, E, se da como sigue;

E = \dfrac{k \cdot Q}{r^2}

La magnitud de la carga, Q = 24 μC

La distancia donde se mide el campo, r = 48 mm = 0.048 m

Por lo tanto, E = 9.0 × 10⁹ × 12 × 10⁻⁶ / 0.048² = 46,875,000 N / C

La intensidad de un campo eléctrico, E = 46,875,000 N / C = 46.875 × 10⁶ N / C

3. La magnitud de las cargas son;

Q₁ = 24 mC

Q₂ = -12 μC

La distancia entre las cargas, r = 0.032 m

un. El potencial eléctrico de una carga, U_E , se da de la siguiente manera;

U_E = k \times \dfrac{Q_1 \cdot Q_2}{r}

Por lo tanto;

U_E = 9.0×10⁹ × 24 × 10⁻³ × (-12) × 10⁻⁶ /0.032 = -81,000

La energía potencial eléctrica entre la carga, Q₁ y Q₂= -81,000 J

b. El potencial eléctrico de Q₁ en Q₂, V₁ = k \times \dfrac{Q_1 }{r}

Por lo tanto, V₁ = 9.0×10⁹ × 24 × 10⁻³/0.032 = 6.75 × 10⁹

El potencial eléctrico de Q₁ en Q₂, V₁ = 6.75 × 10⁹ V

3 0
3 years ago
What is the number of daylight hours of daylight difference in the summer for two regions located at different latitudes in the
ruslelena [56]
To be completely honest the answer is 74
4 0
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A conceptual model is based off of
Klio2033 [76]
<h2>Answer</h2>

Tha conceptual model depends upon the process flow.

<h2>Explanation</h2>

The conceptual model is actually used in the system to stimulate, understand or explore the subject for the better understanding of people. As it consists of different constituents as validation, implementation, accreditation etc. can be affected by the process flow. The process flow has actually consisted of the management, monitoring of objects for specific subject and scales under these monitoring or management are proceedings. As these scales of process flow effects, the objectives of the task impacts.

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Identify and describe three specific mnemonic techniques you learned about and explain how each of these mnemonics devices may b
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3 years ago
A 0.3 g mosquito is flying toward a girl with a speed of 4.5 mph. Just before landing on the girl, the fly is swatted straight b
luda_lava [24]

Answer:

1.1x10^-2N

Explanation:

We have the change in momentum as

P = 0.3(4.5+12)g.mph

= 0.3x0.447x(4.5+12)x10^-3

Then the force that is exerted will be

F = p/∆t

∆t = 0.2

= 0.3x0.447x(4.5+12)x10^-3/0.2

= 0.1341x16.5x10^-3/0.2

= 1.1x10^-2

Therefore the force that was exerted is equal to 1.1x10^-2

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