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zlopas [31]
3 years ago
7

How much energy does the electron have initially in the n=4 excited state?what is the change in energy if the electron from part

a now drops to the ground state?
Physics
1 answer:
Ierofanga [76]3 years ago
8 0
What it looks to be that you found in A was the "initial"...b/c the question asks: 
<span>"how much energy does the electron have 'initially' in the n=4 excited state?" </span>

<span>"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. </span>

The answer comes to: <span>−1.36×10^−19 J</span>


You use the same equation for the second part as for part a. 
<span>just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer. </span>
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Answer:

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a). Find the graph attached for the motion.

b). If a shopper walk 5.4 m westwards then 7.8 m eastwards,

   Distance traveled by the shopper = Distance traveled in eastwards + Distance traveled westwards

                                                            = 5.4 + 7.8

                                                            = 13.2 m

c). Displacement of the shopper = Distance walked westwards - Distance traveled eastwards

                                                      = 5.4 - 7.8

                                                      = -2.4 m

Therefore, magnitude of the displacement of the shopper is = 2.4 m

And the direction of the displacement is eastwards.

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storchak [24]

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Explanation:

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3 years ago
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Answer:

<h2>2.35 N</h2>

Explanation:

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From the question

force = 0.49 × 4.8 = 2.352

We have the final answer as

<h3>2.35 N</h3>

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