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zlopas [31]
3 years ago
7

How much energy does the electron have initially in the n=4 excited state?what is the change in energy if the electron from part

a now drops to the ground state?
Physics
1 answer:
Ierofanga [76]3 years ago
8 0
What it looks to be that you found in A was the "initial"...b/c the question asks: 
<span>"how much energy does the electron have 'initially' in the n=4 excited state?" </span>

<span>"final" would be where it 'finally' ends up at, ie. its last stop...as for this question...the 'ground state' as in its lowest energy level. </span>

The answer comes to: <span>−1.36×10^−19 J</span>


You use the same equation for the second part as for part a. 
<span>just have to subract the 2 as in the only diff for part 2 is that you use 1squared rather than 4squared & subract "final -initial" & you should get -2.05*10^-18 as your answer. </span>
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Answer:

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4 0
3 years ago
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3 years ago
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notka56 [123]

Answer:

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p_i = p_f

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0=mv+MV

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7 0
2 years ago
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madam [21]

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Explanation:

8 0
2 years ago
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Answer:

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