Explanation:
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How much energy does the electron have initially in the n=4 excited state?what is the change in energy if the electron from part
1 answer:
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Answer:
λ = a
Explanation:
This is a diffraction exercise that is described by the expression
a sin θ = m λ
sin θ = m λ/ a
the first zero of the diffraction occurs for m = 1
sin θ = λ / a
angles are generally very small and are measured in radians
sin θ = θ = y / x
we substitute
the width of the central maximum is twice the distance to zero
w = 2y
in the exercise indicate that this width is equal to twice the distance to the screen (2x)
W = 2x
2y = 2x
we substitute
1 = λ/ a
λ = a
we see that the width of the slit is equal to the wavelength used.
The distance covered by the plane is 600 km
Explanation:
The motion of the plane is a uniform motion, so at constant velocity, therefore we can use the following equation
where
d is the distance covered
v is the velocity
t is the time interval considered
For the plane in this problem,
v = 400 km/h
t = 1.5 h
Substituting, we find the distance covered:
Learn more about distance:
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