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irina1246 [14]
3 years ago
8

What happens when current flows through a wire?

Chemistry
1 answer:
Serhud [2]3 years ago
8 0

Answer: Two effects may occur during high current flow: 1) the wire may become overheated to the point that surface oxidation or even evaporation may take place, 2) at the connection points at each end of the wire, especially if the terminations are of a different type of metal than the wire, some atoms may migrate into or out of the wire.

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What would be the final volume (in mL) of the aqueous potassium fluoride which was prepared by dissolving 8.0 g of potassium flu
zhuklara [117]

Answer:

0.15 L

Explanation:

Step 1. Calculate the <em>moles of KF.</em>

Molar mass = 58.10 g/mol

Moles of KF = 8.0 × 1/58.10  

Moles of KF = 0.138 mol KF

===============

Step 2. Calculate the <em>volume of KF </em>

c = n/V                  Multiply both sides by V

V = 0.138 × 1/0.89  

V = 0.15 L



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4 years ago
Calculate ΔH⁰298 (in kJ) for the process P(s) + 5/2 Cl2(g) → PCl5(g) from the following information.
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Answer:

\Delta H_{298}^{0} for the process is -375 kJ

Explanation:

  • Given reaction is a combination of the two given elementary steps.
  • Summation of change in standard enthalpy (\Delta H_{298}^{0})of the two elementary reactions give \Delta H_{298}^{0} of the reaction P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g).

P(s)+\frac{3}{2}Cl_{2}(g)\rightarrow PCl_{3}(g)......\Delta H_{1}=-287kJ

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-----------------------------------------------------------------------------------------------------

P(s)+\frac{5}{2}Cl_{2}(g)\rightarrow PCl_{5}(g)

\Delta H_{298}^{0} = \Delta H_{1}+\Delta H_{2}=-287kJ-88kJ=-375kJ

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Which desribes a step in the process of forming and ionic bond
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Explanation:

A metal atom loses electrons and becomes a positive ion.

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