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Elza [17]
3 years ago
12

Pick any habitat and model a food web to illustrate the flow of food energy. Those were your teacher’s instructions. You created

a beautiful drawing as your model, as seen here, but your teacher commented that it was not accurate. What is an important limitation of your food web? A) Your model is not in color. B) It is not a web; it is a chain. C) The scale of your drawings are inaccurate. D) It does not show how similar organisms use energy.
Chemistry
1 answer:
Dafna11 [192]3 years ago
5 0

It's not a food web it's a food chain. I just did the exam a few minutes ago. Please mark it Brainliest.

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An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu
chubhunter [2.5K]

Answer:

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

The density of a proton is 6.278\times 10^{14} g/cm^3.

Explanation:

Diameter of the atom ,d = 2.50 Å

Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\pi r^3..[1]

Diameter of the nucleus ,d' = 9.00\times 10^{-5}\AA

Radius of the nucleus ,r' = 0.5 d'=0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA

Volume of nucleus = V'

V=\frac{4}{3}\pi r'^3..[2]

Dividing [2] by [1]

\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}

=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}

\frac{V'}{V}=4.6656\times 10^{-14}

The fraction of the volume of the atom that is taken up by the nucleus is 4.6656\times 10^{-14}.

Diameter of the proton ,d = 1.72\times 10^{-15} m = 1.72\times 10^{-13} cm

1 m = 100 cm

Radius of the proton,r = 0.5 d=0.5\times 1.72\times 10^{-13} cm=8.6\times 10^{-14} cm

Volume of the sphere= \frac{4}{3}\pi r^3

Volume of atom = V

V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3

Mass of proton, m = 1.0073 amu = 1.0073\times 1.66054\times 10^{-24} g

1 amu = 1.66054\times 10^{-24} g

Density of the proton : d

d=\frac{m}{V}=\frac{1.0073\times 1.66054\times 10^{-24} g}{2.664\times 10^{-39}cm^3}=6.278\times 10^{14} g/cm^3

The density of a proton is 6.278\times 10^{14} g/cm^3.

5 0
3 years ago
What would happen if N2 were added to N2(g) + O2(g) = 2NO(9) at
DerKrebs [107]

Balanced chemical equation is :

N_2(g)+O_2(g)-->2NO(g)

It is given that the equation is in equilibrium.

We need to find what will happen if we add more N_2 is added .

By Le Chatelier's principle :

Changing the concentration of a chemical will shift the equilibrium to the side that would counter that change in concentration.

It means production of the side where content is added will decrease and concentration on other side will increase .

So , more NO would form .

Therefore, option B. is correct.

Hence, this is the required solution.

4 0
2 years ago
Describe the main difference between the Bohr model of the atom and the Rutherford model.
atroni [7]

Answer:

The main difference between the two models was about the location of the electron in an atom.

Explanation:

<u>Rutherford described that:</u>

  • The electrons were outside of the nucleus.
  • They were equal in number to the "positiveness" of the nucleus.
  • Also, He randomly placed the negative electrons outside the nucleus.

<u>Bohr improved the Rutherford model:</u>

  • Bohr placed the electrons in distinct energy levels.
  • Electrons only exist in fixed orbitals (shells) and not anywhere in between.
  • Each shell has a fixed energy
  • Rutherford explained the nucleus of an atom, while Bohr was more into the electrons and their energy levels.

8 0
2 years ago
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Find the distance between two points rounding to the nearest tenth<br> (-7,-1) and (-4,3)
qaws [65]
The beast tenth is 2 cause it’s close to both
8 0
2 years ago
If the atomic number of an element is 9 and the mass number is 19, how many neutrons does the atom have?
sammy [17]
To find the number of neutrons.....

NEUTRONS = MASS NUMBER - ATOMIC NUMBER ( PROTONS)

NEUTRONS  =  19  -  9 

So this element has 10 neutrons
5 0
2 years ago
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