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liubo4ka [24]
1 year ago
14

Grady is doing an experiment about the solubility of sugar. He puts 100 milliliters of water in each of three beakers. He leaves

the first beaker at room temperature, heats the second beaker to 60°C, and heats the third beaker until the water boils at 100°C.
To the first beaker, he adds sugar, one spoonful at a time, until not all of the sugar can dissolve when he stirs it. He records the number spoonfuls that dissolved. Then he repeats the same process of adding sugar and stirring for the beakers of hot water and boiling water
Chemistry
1 answer:
drek231 [11]1 year ago
4 0

Variables within an experiment many be altered in order to produce specific outcomes such as a reaction rate. The reaction rate is a measure of how fast a chemical reaction can happen. The increase in temperature increases the collision of molecules, such as the solid sugar solute and and the water molecules, which act as a solvent. Agitation, such as stirring, also increases the solubility by increasing collisions.

This continues until the solution becomes too saturated.

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A plant release it’s seed , but soon there after, the area seeds are in experiences a yearlong drought. How would the seeds most
SOVA2 [1]

Answer:

Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.

Explanation:

Plants will absorb water through their roots and release water as vapor into the air through these stomata. To survive in drought conditions, plants need to decrease transpiration to limit their water loss. Some plants that live in dry conditions have evolved to have smaller leaves and therefore fewer stomata.

6 0
3 years ago
How many grams of KCIO3 are needed to produce 5.00 of O2 at STP?
Arlecino [84]
2KClO₃ → 2KCl + 3O₂

mole ratio of KClO₃ to O₂ is 2 : 3

∴ if moles of O₂ = 5 mol

then moles of KClO₃ = \frac{5 mol   *   2}{3}

                            = 3.33 mol


Mass of KClO₃ needed = mol of KClO₃ × molar mass of KClO₃

                                      = 3.33 mol × ((39 × 1) + (35.5 × 1) + (16 × 3) g/mol

                                      = 407.93 g
6 0
3 years ago
The microscopes used today are just like the ones used by Leeuwenhoek and Hooke. True or false
Dmitry [639]

Answer:

False

Explanation:

While we do know that A. Leeuwenhoek used a simple microscope that consisted of only 1 lens, Hooke used a compound microscope. Although, after trying a compound microscope, Hooke found out that it strained his eyes and continued to use a simple microscope for his <em>Micrographia</em>.

Thus, we can say that the (compound) microscopes used today are different than the (simple) microscope used by Hooke and Leeuwenhoek.

6 0
2 years ago
The Oxidation number of iron in the Complexion [Fe(CN) 6]³^- is what?​
LUCKY_DIMON [66]

+3

Hence, the magnetic behaviour of the complex is paramagnetic. The oxidation number of the central metal atom: The oxidation number of the metal iron is +3.

4 0
2 years ago
Read 2 more answers
13) 2.4 L to mL<br> This is for chemistry
jolli1 [7]

Answer: 2400 milliters

Explanation:

8 0
3 years ago
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