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scoundrel [369]
3 years ago
6

18 POINTS Just need the correct answer 1-3 Thanks will Make As Brainlist

Physics
2 answers:
Makovka662 [10]3 years ago
8 0
1)D
2)B
3)D

Hope this helps!
NARA [144]3 years ago
8 0
The answer are D B D
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I don't know how to solve this please help
Luden [163]
Energy = mass * SHC * temp change


Temp change = energy/SHC * mass

42kJ - 42000J (convert kJ to J as energy is counted as J/kg)

Temp change = 42000/4200*10
= 1C

So it goes up by 1C thus the final temperature would be 26C


Or a more logical way to think of it would be that if it takes 4200J to heat up 1kg of water by 1C (SHC is 4200J/kgC) it would take ten times the amount of energy to heat up 10kg of water by 1C hence it takes 42000J.
7 0
3 years ago
Ashen light (or earthshine) is
Annette [7]

Answer:

E

Explanation:

The condition known as Earth shine takes place when the reflecting sunlight from our world illuminates the Moon's dark side. This is usually the result that the dark side of the moon is showered in a dim, faint light. It is also called  as the ashen light of the Moon, or in the wings of the new Moon as the old Moon.

Therefore the correct reason would be e. sunlight reflected by Earth that illuminates the "dark" portion of the Moon.

8 0
3 years ago
This system filters wastes from the blood
Gekata [30.6K]
The excretory system is responsible for removing waste from the body
3 0
3 years ago
Read 2 more answers
A rectangular gasoline tank can hold 50.0 kg of gasoline when full. What is the depth of the tank if it is 0.500-m wide by 0.900
sweet-ann [11.9K]

Answer:

0.16 m

Explanation:

A rectangular gasoline tank can hold 50.0 kg of gasoline when full, and the density of gasoline is 6.8 × 10² kg/m³. We can find the volume occupied by the gasoline (volume of the tank).

50.0 kg × (1 m³/6.8 × 10² kg) = 0.074 m³

The volume of the rectangular tank is:

volume = width × length × depth

depth = volume / width × length

depth = 0.074 m³ / 0.500 m × 0.900 m

depth = 0.16 m

3 0
3 years ago
A 1.45 kg falcon catches a 0.515 kg dove from behind in midair. What is their velocity after impact if the falcon's velocity is
True [87]

Answer:

Their velocity after the impact is 20.85 m/s.                            

Explanation:

Given that,

Mass of falcon, m_1=1.45\ kg

Mass of dove, m_2=0.515\ kg

Initial speed of the falcon, u_1=26.5\ m/s

Initial speed of the dove, u_2=4.95\ m/s

We need to find the final velocity after the impact. When the falcon catches the dove, it will becomes the case of inelastic collision. The conservation of momentum will be :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{1.45\times 26.5+0.515\times 4.95}{(1.45+0.515)}\\\\V=20.85\ m/s

So, their velocity after the impact is 20.85 m/s.                          

8 0
3 years ago
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