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emmasim [6.3K]
3 years ago
11

Two air track carts move along an air track towards each other. Cart A has a mass of 450 g and moves toward the right with a spe

ed of 0.850 m/s and air track cart B has a mass of 300 g and moves toward the left with a speed of 1.12 m/s. What is the total momentum of the system
Physics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

0.465 kgm/s

Explanation:

Given that

Mass of the cart A, m1 = 450 g

Speed of the cart A, v1 = 0.85 m/s

Mass of the cart B, m2 = 300 g

Speed of the cart B, v2 = 1.12 m/s

Now, using the law of conservation of momentum.

It is worthy of note that our cart B is moving in opposite directions to A

m1v1 + m2v2 =

(450 * 0.85) - (300 * 1.12) =

382.5 - 336 =

46.5 gm/s

If we convert to kg, we have

46.5 / 100 = 0.465 kgm/s

Thus, the total momentum of the system is 0.465 kgm/s

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Express the answer to 4.31x10^7 multiplied by 5.41x10^5 scientific notation.
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Answer:

The product of the two numbers is 2.33* 10^13

Explanation:

Given

4.31x10⁷ and 5.41x10⁵

Required

Multiply

The multiplication of the two digits is represented as thus:

Result = 4.31 * 10^7 * 5.41 * 10^5

This can also be rewritten as

Result = 4.31 * 5.41 * 10^7 * 10^5

Multiply 4.31 and 5.41

Result = 23.3171 * 10^7 * 10^5

Apply laws of indices

Result = 23.3171 * 10^{7+5}

Result = 23.3171 * 10^{12}

The scientific notation is always in the form: a * 10^n

Where 1 \leq\ a \leq 10

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23.3171 can be rewritten as 2.33171 * 10

So, we have:

Result = 2.33171 * 10* 10^{12}

Also, apply law of indices again

Result = 2.33171 * 10^{1+12}

Result = 2.33171 * 10^{13}

It's always advisable (but not compulsory to approximate to 1 or 2 decimal places)

So:

Result = 2.33* 10^{13}

<em>Hence; the product of the two numbers is 2.33* 10^13</em>

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A. 131 V

I got it right on the quiz

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