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Stels [109]
3 years ago
10

Why to astronauts appear weightless while they are filmed performing activities inside the orbiting space shuttle?

Physics
2 answers:
vagabundo [1.1K]3 years ago
8 0
<h2>Answer: The astronauts are falling at the same rate as the space shuttle as it orbits around earth</h2>

The astronauts seem to float because they are in free fall just like the spacecraft.

However, although they are constantly falling on the Earth, they do not fall because the ship orbits at a sufficient speed (in the same direction of rotation of the Earth) so that the centrifugal force is balanced with the Earth's gravitational pull.

In other words:

The spaccraft and the astronauts are in free fall but the Earth's surface will never be reached as long as they does not decrease the speed.

Then, as they accelerate toward Earth (regardless of their mass), it curves beneath them and never comes close.

That's why astronauts, having the same acceleration as the spacecraft, feel weightless and see themselves floating.

Alexeev081 [22]3 years ago
5 0

Answer:

an astronaut is under the gravitational force of any object nearby that has mass.

Explanation:

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valina [46]

Answer: 0.78m/s^2

Explanation:

Force is the product of mass of an object and its acceleration.

i.e Force = Mass x Acceleration

In this case,

Force applied on cart = 35N

Mass of cart and contents = 45Kg

Acceleration = ?

Then, Force = Mass x Acceleration

35N = 45Kg x Acceleration

Acceleration = (35N/45kg)

Acceleration = 0.78 m/s^2 (The unit of acceleration is metre per second square)

Thus, the shopping cart moved with an accelerations of 0.78m/s^2

8 0
3 years ago
Two vectors pointing right starting at the same position. Vector A is on top and longer. Vector B is shorter and below.
Oksana_A [137]

Answer:

The displacements are not equal. While their direction is the same, their length (i.e., distance or magnitude) is not. A is longer than B.

Explanation:

correct on e2020- sample respnse

4 0
3 years ago
Read 2 more answers
Consider an alcohol and a mercury thermometer that read exactly 0 oC at the ice point and 100 oC at the steam point. The distanc
Alexeev081 [22]

Answer:

No, both the thermometers will give the different reading.

Explanation:

Given,

  • Both thermometer has same ice point = T_i\ =\ 0^o C
  • Both thermometer has same steam point = T_s\ =\ 100^o C
  • Distance between the ice point and steam point in both the thermometer is same of 100 division,

All the data given in both the thermometers are same, but the material in the thermometer is different due to this the reading at 60^o C will differ in both the thermometer. Because the reading on both the thermometer is depended upon the thermal expansion of the material inside it, but both the materials are different. Due to this the rise of fluid in the thermometer, i,e,. the volume of the fluid material in the thermometer will depend upon the thermal expansion.  Hence both the material alcohol and mercury have the different thermal expansion, therefore the rise of the fluid in the thermometer also differ in both the thermometer.

7 0
3 years ago
No matter what values of m and k you used for the spring, what is the ratio of the period to k m.
Leto [7]

The relationship between the period of an oscillating spring and the attached mass determines the ratio of the period to \sqrt{\dfrac{m}{k} }.

Response:

  • The ratio of the period to  \sqrt{\dfrac{m}{k} } is always approximately<u> 2·π : 1</u>

<u />

<h3>How is the value of the ratio of the period to \sqrt{\dfrac{m}{k} } calculated?</h3>

Given:

The relationship between the period, <em>T</em>, the spring constant <em>k</em>, and the

mass attached to the spring <em>m</em> is presented as follows;

T =  \mathbf{2 \cdot \pi \cdot \sqrt{\dfrac{m}{k} }}

Therefore, the fraction of of the period to \sqrt{\dfrac{m}{k} }, is given as follows;

\mathbf{\dfrac{T}{ \sqrt{\dfrac{m}{k} }}} = 2 \cdot \pi

2·π ≈ 6.23

Therefore;

T :{ \sqrt{\dfrac{m}{k} }} = 2 \cdot \pi : 1

Which gives;

  • The ratio of the period to  \sqrt{\dfrac{m}{k} } is always approximately<u> 2·π : 1</u>

Learn more about the oscillations in spring here:

brainly.com/question/14510622

7 0
3 years ago
What do the spheres in the model represent
Sophie [7]

Answer: no

Explanation: we need a picture

4 0
3 years ago
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