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3 years ago

Why to astronauts appear weightless while they are filmed performing activities inside the orbiting space shuttle?

Physics

2 answers:

vagabundo [1.1K]3 years ago

8 0

<h2>Answer: The astronauts are falling at the same rate as the space shuttle as it orbits around earth</h2>

The astronauts seem to float because they are in free fall just like the spacecraft.

However, although they are constantly falling on the Earth, they do not fall because the ship orbits at a sufficient speed (in the same direction of rotation of the Earth) so that the centrifugal force is balanced with the Earth's gravitational pull.

In other words:

The spaccraft and the astronauts are in free fall but the Earth's surface will never be reached as long as they does not decrease the speed.

Then, as they accelerate toward Earth (regardless of their mass), it curves beneath them and never comes close.

That's why astronauts, having the same acceleration as the spacecraft, feel weightless and see themselves floating.

Alexeev081 [22]3 years ago

5 0

Answer:

an astronaut is under the gravitational force of any object nearby that has mass.

Explanation:

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43. A rocket sled accelerates at a rate of 49.0m/s2. Its passenger has a mass of 75.0 kg. (a) Calculate the horizontal component

lord [1]

(a) 3675 N

Assuming that the acceleration of the rocket is in the horizontal direction, we can use Newton's second law to solve this part:

$F_x = m a_x$

where

$F_x$ is the horizontal component of the force

m is the mass of the passenger

$a_x$ is the horizontal component of the acceleration

Here we have

m = 75.0 kg

$a_x = 49.0 m/s^2$

Substituting,

$F_x=(75.0)(49.0)=3675 N$

(b) 3748 N, 11.3 degrees above horizontal

In this part, we also have to take into account the forces acting along the vertical direction. In fact, the seat exerts a reaction force (R) which is equal in magnitude and opposite in direction to the weight of the passenger:

$R=mg=(75.0)(9.8)=735 N$

where we used

$g=9.8 m/s^2$ as acceleration of gravity.

So, this is the vertical component of the force exerted by the seat on the passenger:

$F_y = 735 N$

and therefore the magnitude of the net force is

$F=\sqrt{F_x^2+F_y^2}=\sqrt{3675^2+735^2}=3748 N$

And the direction is given by

$\theta = tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{735}{3675})=11.3^{\circ}$

4 0

3 years ago

3. How did Kepler's work influence Newton?

Katarina [22]

Johannes Kepler and his laws were a great influence on Isaac Newton. ... Newton used his laws of gravity and motion to derive Kepler's laws and show that the motion of the planets could be explained using mathematics and physics.

3 0

3 years ago

Read 2 more answers

What must you do to calculate a meaningful value of distance from the following equation?

ss7ja [257]

Answer:

Convert all the times to either hours or seconds

Explanation:

One time unit is in hours, and the other is in seconds. In order to do the math, the units need to be the same. So you either need to convert hours to seconds, or seconds to hours.

5 0

3 years ago

Read 2 more answers

Fill in the blanks to complete the statements.

Murljashka [212]

Answer:

When an object changes speed (increases/decreases) it results in acceleration/de acceleration, its velocity also changes.

Explanation:

Acceleration is the rate of change in velocity.An object can accelerate when speed increases, decreases or direction changes. All these instances involves a change in velocity.Velocity is a vector quantity thus it has magnitude and the direction.Acceleration due to change in direction is centripetal acceleration.The expression for finding acceleration is;

a=change in velocity/change in time

a=Δv/Δt in m/s²

3 0

3 years ago

A car with an initial speed of 23.7 km/h accelerates at a uniform rate of 0.92 m/s for 3.6 s. Find the final speed of the car du

jasenka [17]

Answer: Final speed of car is 9.99 ≈10m/s or 2.78 km/h

Explanation:

Initial speed V1=23.7 km/h=6.58 m/s

accelerationa=0.92 m/s²

Time: t=3.6 s

V2=?

---------------------

use equat.

a=(V2-V1)/t

from here we can find V2

a*t=V2-V1

a*t+V1=V2

V2=a*t+V1

V2=0.92m/s²*3.6+6.58m/s

V2=3.312m/s+6.68m/s

V2=9.99m/s ≈10m/s

3 0

3 years ago