Since the point lies on the unit circle, it satisfies
Solving for
gives two possible solutions:
Given that
is in quadrant IV, you know that its value must be positive, so
You must do 6 to the second power then plug in 3 for M which gives you 36/2(3), multiply 2 times 3 to get 6 then divide. Your answer is 6.
Answer:
Step-by-step explanation:
Since we are to show by Pythagoras that the square will fit inside the circle without touching the edge of the circle , this means that we must find the value of the length of the diagonal of the square using Pythagoras.
For the square to fit in without touching the edge of the circle , this means that the diagonal of the square must be less than the diameter of the circle.
Length of the square is 5cm.
Recall Pythagoras theorem: it states that
the square on the hypotenuse of a right-angled triangle is equal in area to the sum of the squares on the other two sides
= +
= 25 + 25
= 50
Take the square root of both sides , that is
D =
D = X , since 50 = 25 x 2
D = 5
D ≈ 7.07
The upper quartile is 9
Lower quartile: 5
Median: 8
Upper quartile: 9
Answer:
the answer is c
Step-by-step explanation:
add the sum
