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Rasek [7]
2 years ago
12

Expand. If necessary, combine like terms. (3 + 4x) (3 - 4x)

Mathematics
1 answer:
shepuryov [24]2 years ago
5 0
  • (3 + 4x) (3 - 4x)

We know the algebraic identity: (a - b)(a + b) = a^2 + b^2. Therefore, we should square 3 and 4x.

  • = (3)^2 - (4x)^2
  • 9 - 16x^2

<u>Answer</u><u>:</u>

<u>9</u><u> </u><u>-</u><u> </u><u>1</u><u>6</u><u>x</u><u>^</u><u>2</u>

Hope you could understand.

If you have any query, feel free to ask

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Brad wants to buy flowers for his friend with $33. The daisies are $1 each and the roses are $3 each. He buys 3 more daisies tha
Darina [25.2K]

Let x=the amount of roses that Brad buys. (x+3)=the number of daisies that Brad buys.


x+(x+3)=33


Simplify this problem to find the amount of roses:


2x+3=33


2x=30


x=15


So, Brad buys 15 roses and 18 daisies.


Since roses cost $3, 15*3=45.


The roses cost $45.


Hope this helps! :)

8 0
3 years ago
What is. 9 divided by 204
gulaghasi [49]
Is that .9?  or was that period mark accidental?
8 0
3 years ago
Tell me a please is a time limit on this
Masteriza [31]

Answer:

A

Step-by-step explanation:

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7 0
2 years ago
Read 2 more answers
Simplify: log base 3 (1/3) ...?
yarga [219]
The answer is 1.

log_3( \frac{1}{3} )
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Since log_y(x) =  \frac{log_{10}(x)}{log_{10}(y)}, then: log_3( \frac{1}{3} )= \frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)}
_____
Since \frac{1}{x} = x^{-1}, then: \frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)} = \frac{log_{10}(3^{-1} )}{log_{10}(3)}
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Since log x^{a} =a*logx, then: \frac{log_{10}(3^{-1} )}{log_{10}(3)}= \frac{-1*log_{10}(3)}{log_{10}(3)}

From here: \frac{-1*log_{10}(3)}{log_{10}(3)}=-1*\frac{log_{10}(3)}{log_{10}(3)}=-1*1 = -1

6 0
2 years ago
What is the steps for this (-11)(-9)(-14) ​
harina [27]

Answer:

Here's ur ans buddy...PLZ mark it as brainliest ✌️✌️✌️

Step-by-step explanation:

( - 11)( - 9)( - 14) \\ ( - 20)( - 14) \\ ( - 34)

3 0
3 years ago
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