All categories

2 years ago

Expand. If necessary, combine like terms. (3 + 4x) (3 - 4x)

Mathematics

1 answer:

shepuryov [24]2 years ago

5 0

(3 + 4x) (3 - 4x)

We know the algebraic identity: (a - b)(a + b) = a^2 + b^2. Therefore, we should square 3 and 4x.

= (3)^2 - (4x)^2
9 - 16x^2

Answer:

9 - 16x^2

Hope you could understand.

If you have any query, feel free to ask

You might be interested in

Brad wants to buy flowers for his friend with $33. The daisies are $1 each and the roses are $3 each. He buys 3 more daisies tha

Darina [25.2K]

Let x=the amount of roses that Brad buys. (x+3)=the number of daisies that Brad buys.

x+(x+3)=33

Simplify this problem to find the amount of roses:

2x+3=33

2x=30

x=15

So, Brad buys 15 roses and 18 daisies.

Since roses cost $3, 15*3=45.

The roses cost $45.

Hope this helps! :)

8 0

3 years ago

What is. 9 divided by 204

gulaghasi [49]

Is that .9? or was that period mark accidental?

8 0

3 years ago

Tell me a please is a time limit on this

Masteriza [31]

Answer:

Step-by-step explanation:

(4+5)7=9*7=63

7 0

2 years ago

Read 2 more answers

Simplify: log base 3 (1/3) ...?

yarga [219]

The answer is 1.

$log_3( \frac{1}{3} )$
_____
Since $log_y(x) = \frac{log_{10}(x)}{log_{10}(y)}$ , then: $log_3( \frac{1}{3} )= \frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)}$
_____
Since $\frac{1}{x} = x^{-1}$ , then: $\frac{log_{10} ( \frac{1}{3}) }{log_{10}(3)} = \frac{log_{10}(3^{-1} )}{log_{10}(3)}$
_____
Since $log x^{a} =a*logx$ , then: $\frac{log_{10}(3^{-1} )}{log_{10}(3)}= \frac{-1*log_{10}(3)}{log_{10}(3)}$

From here: $\frac{-1*log_{10}(3)}{log_{10}(3)}=-1*\frac{log_{10}(3)}{log_{10}(3)}=-1*1 = -1$

6 0

2 years ago

What is the steps for this (-11)(-9)(-14)

harina [27]

Answer:

Here's ur ans buddy...PLZ mark it as brainliest ✌️✌️✌️

Step-by-step explanation:

$( - 11)( - 9)( - 14) \\ ( - 20)( - 14) \\ ( - 34)$

3 0

3 years ago