Given:3.40g sample of the steel used to produce 250.0 mLSolution containing Cr2O72−
Assuming all the Cr is contained in the BaCrO4 at the end.
(0.145 g BaCrO4) / (253.3216 g BaCrO4/mol) x (250.0 mL / 10.0 mL) x (1 mol Cr / 1 mol BaCrO4) x (51.99616 g Cr/mol / (3.40 g) = 0.219 = 21.9% Cr
Both ehhevshahahbsbdvhshs
Answer:
The answer to your question is the letter C. three times as much
Explanation:
Data
First step = 6 m
Second step = 18 m
Potential energy is the energy stored that depends on its position.
Formula
Pe = mgh
m = mass; g = gravity; h = height
Potential energy of the first step
Pe1 = 6mg
Potential energy of the second step
Pe2 = 18mg
-Divide the Pe2 by the Pe1
Pe2/Pe1 = 18mg/6mg
= 3
Answer:
D:2
Explanation:
H is hydrogen, and the subscript represents the amount of atoms it has so H2SO is two hydrogens
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