1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga55 [171]
3 years ago
7

A cylinder with a movable piston originally has a volume of 2805 mL and is filled with nitrogen to a pressure of 4.00

Chemistry
1 answer:
Sergio039 [100]3 years ago
6 0

This problem is providing the initial volume and pressure of nitrogen in a piston-cylinder system and asks for the final pressure it will have when the volume increases. At the end, the answer turns out to be 2.90 atm.

<h3>Boyle's law</h3>

In chemistry, gas laws are used so as to understand the volume-pressure-temperature-moles behavior in ideal gases and relate different pairs of variables.

In this case, we focus on the Boyle's law as an inversely proportional relationship between both pressure and volume at constant both temperature and moles:

P_1V_1=P_2V_2

Thus, we solve for the final pressure by dividing both sides by V2:

P_2=\frac{P_1V_1}{V_2}

Hence, we plug in both the initial pressure and volume and final volume in order to calculate the final pressure:

P_2=\frac{2805mL*4.00atm}{3864mL}\\ \\P_2=2.90atm

Learn more about ideal gases: brainly.com/question/8711877

You might be interested in
What type of compound is formed when a secondary (2°) alcohol is treated with Jones' reagent?
EastWind [94]

Answer:

Option D, ketone

Explanation:

Since Jones reagent (CrO3/H2SO4) is a strong oxidizing agent and oxidize the secondary alcohol to ketone.

Example , isopropanol gets oxidized to propanone.

Primary Alcohol gets oxidized to Carboxylic acids.

6 0
4 years ago
Can somebody please help me ! :(
Helen [10]

Answer:

325

Explanation:

velocity = 3250 Hz x 0.1 m

5 0
3 years ago
Read 2 more answers
A solution with a hydrogen ion concentration of 3.25 × 10-2 m is ________ and has a hydroxide concentration of _______
Romashka-Z-Leto [24]

To know the acidity of a solution, we calculate the pH value. The formula for pH is given as:

<span>pH = - log [H+]            where H+ must be in Molar</span>

We are given that H+ = 3.25 × 10-2 M

Therefore the pH is:

pH = - log [3.25 × 10-2] 

pH = 1.488

Since pH is way below 7, therefore the solution is acidic.

 

To find for the OH- concentration, we must remember that the product of H+ and OH- is equivalent to 10^-14. Therefore,

[H+]*[OH-] = 10^-14 <span>
</span>[OH-] = 10^-14 / [H+]

[OH-] = 10^-14 / 3.25 × 10-2

[OH-] = 3.08 × 10-13 M

 

Answers:

Acidic

[OH-] = 3.08 <span>× 10-13 M</span>

6 0
3 years ago
Suppose a student started with 142.0 mg of trans-cinnamic acid, 412 mg of pyridinium tribromide, and 2.30 mL of glacial acetic a
nirvana33 [79]

Answer: Theoretical Yield = 0.2952 g

               Percentage Yield = 75.3%

Explanation:

Calculation of limiting reactant:

n-trans-cinnamic acid moles = (142mg/1000) / 148.16 = 9.584*10⁻⁴ mol

pyridium tribromide moles = (412mg/1000) / 319.82= 1.288*10⁻³ mol

  • n-trans-cinnamic acid is the limiting reactant

The molar ratio according to the equation mentioned is equals to 1:1

The brominated product moles is also = 9.584*10⁻⁴ mol

Theoretical yield = (9.584*10⁻⁴ mol) * (Mr of brominated product)

                             =  (9.584*10⁻⁴ mol) * (307.97) = 0.2952 g

Percentage Yield is : Actual Yield / Theoretical Yield = 0.2223/0.2952

                                                                                           = 75.3%

4 0
3 years ago
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
a_sh-v [17]

Answer:

m_{H_2O}=39.0g

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g

Best regards.

8 0
3 years ago
Other questions:
  • 55.845 nearest tenth
    15·2 answers
  • if 50.0 ml of a 1.00 M HCl solution and 45.0 ml of a 1.00 M NaOH solution are combined, which reagent is limiting?
    10·2 answers
  • Lewis Dot structure for N2?<br> PHOTO ABOVE <br><br> Is not D I got it wrong
    7·1 answer
  • The variable n represents
    8·1 answer
  • Pick a one world factor to describe the benefits and limitations of Bromine
    9·1 answer
  • How many molecules of water of hydration surround each molecule of sodium carbonate decahydrate, Na2CO3•10H2O
    6·2 answers
  • Carbon dioxide in the oceans is affecting its pH.<br><br> a. True<br> b. False
    11·1 answer
  • What is the change in enthalpy when 180 g of water vapor condenses at 100°C? (AH, = 40.67 kJ/mol)
    6·1 answer
  • Is it possible to have a bent molecule without a molecular dipole?
    10·1 answer
  • What is the mass percentage of Li2CO3
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!