The correct answer would be option 1. The mole ratio of butane to carbon dioxide is 1:4. Looking at the balanced chemical reaction, we see that we need 2 moles of butane to produce 8 moles of carbon dioxide. So, it is 2:8. Simplifying this by dividing both to 2, we have 1:4.
Answer:
893K=620 °C
Explanation:
PV=nRT
P=nRT/V
P= (1 mol* 0.0821* 298K)/15L P=1.63 atm
T=PV/nR
T=(1.63 atm*45 L)/(1 mol*0.0821)
T= 893K=620 °C
Answer:
285g of fluorine
Explanation:
To solve this problem we need to find the mass of Freon in grams. Then, with its molar mass we can find moles of freon and, as 1 mole of Freon, CCl₂F₂, contains 2 moles of fluorine, we can find moles of fluorine and its mass:
<em>Mass Freon:</em>
<em>2.00lbs * (454g / 1lb) = </em>908g of Freon
<em>Moles freon -Molar mass: 120.91g/mol- and moles of fluorine:</em>
908g of Freon * (1mol / 120.91g) =
7.5 moles of freon * (2moles Fluorine / mole Freon): 15 moles of fluorine
<em>Mass fluorine -Atomic mass: 19g/mol-:</em>
15 moles F * (19g / mol) =
<h3>285g of fluorine</h3>
Answer:
Ethanol (boiling point 78°C) and methanol (boiling point 65°C) are two miscible liquids. There is only a small difference in their boiling points. These two liquids are separated from their mixture by fractional ths distillation.
When vapours of the mixture pass through the fractionating column, repeated liquefaction and vapourisation take place. Subsequently, the vapours of low boiling methanol enter the condenser from the fractionating column, condense to liquid and get collected in the round bottomed flask first. Similarly, ethanol with higher boiling point can be collected later in another round bottomed flask.
Due to it's electronic configuration w/c is 1s2 2s2 2ps 3s1 considering the last w/c is 3s1, sodium should be in row 3 period a1.
