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Andreas93 [3]
3 years ago
8

The equilibrium constant, Kc, for the following reaction is 1.55 at 667 K.

Chemistry
1 answer:
scoray [572]3 years ago
3 0

<u>Answer:</u> The concentration of ammonia in the equilibrium mixture is 0.022 M

<u>Explanation:</u>

We are given:

Equilibrium concentration of hydrogen gas = 0.324 M

For the given chemical equation:

                     2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

<u>Initial:</u>                  a

<u>At eqllm:</u>           a-2x           x          3x

Evaluating the value of 'x':

\Rightarrow 3x=0.324\\\\\Rightarrow x=\frac{0.324}{3}=0.108

So, equilibrium concentration of nitrogen gas = x = 0.108 M

Equilibrium concentration of ammonia gas = (a - 2x) = [a - 2(0.108)] = (a - 0.216) M

The expression of K_c for above equation follows:

K_c=\frac{[N_2][H_2]^3}{[NH_3]^2}

We are given:

K_c=1.55

Putting values in above expression, we get:

1.55=\frac{0.108\times 0.324}{(a-0.216)}\\\\a=0.238

Equilibrium concentration of ammonia gas = (a - 0.216) = [0.238 - 0.216] = 0.022 M

Hence, the concentration of ammonia in the equilibrium mixture is 0.022 M

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Write the name of the alkyne next to the drawing of the molecule. (2 points)
azamat

1) 1-Pentyne

2) But-2-yne

3) Ethyne

4) 1-Propyne

5) 1-Butyne

6) Pent-2-yne

<h3>What is alkyne?</h3>

Molecules that contain a triple bond between two carbon atoms are known as alkynes.

1) The number of carbon on the longest chain = 5, (two carbon atoms between the triple bond) therefore the prefix is pen-

The functional group is the triple bond on the first carbon with the suffix -yne

The name of the compound is 1-Pentyne

2) There are 4 carbon atoms on the longest chain, therefore, the prefix is but-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom

Therefore, the name of the compound is But-2-yne

3) The triple bond functional group is between the only two carbon atoms, therefore, the name is Ethyne

4) The number of carbon atoms = 3, with a prefix prop-, and the functional group on the first carbon atom on the longest chain is the triple bond, with suffix -yne

Therefore, the name of the compound is 1-Propyne

5) The number of carbon atoms on the longest chain = 4, the prefix is but-

The location of the triple bond functional group (suffix -yne) is on the first carbon atom

Therefore, the name is 1-Butyne

6) The number of carbon atoms on the longest chain = 5, the prefix of the compound is pen-

The location of the triple bond functional group (suffix; -yne) is on the second carbon atom, therefore;

The name of the compound is Pent-2-yne

Learn more about alkyne here:

brainly.com/question/23508203

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6 0
2 years ago
Al calentar la mantequilla, esta se transforma en liquido, este cambio se denomina?
BlackZzzverrR [31]

Answer:

cambio fisico

Explanation:

4 0
3 years ago
A gas occupies 18.5L at stp. what volume will it occupy at 735 torr and 57°c?
olga nikolaevna [1]

 The volume that  will  be occupied at 735  torr and 57 c  is 23.12 L


 <u><em>calculation</em></u>

  • <u><em> </em></u> At STP   temperature=273 k  and  pressure=760 torr
  • <u><em> </em></u>by use of combined  gas formula

that is P1V1/T1= P2V2/T2

where; P1 =760 torr

           T1= 273  K

           V1= 18.5 L

          P2= 735 torr

         T2=  57+273= 330 K

          V2=?

  • by making   V2 the formula of subject

     V2= T2P1V1/P2T1

       V2=  [(18.5L  x 330 k  x 760 torr)/(735 torr x 273 k)]= 23.12  L




5 0
3 years ago
If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?
padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, t_{(1/2)} = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }

For two half lives, t = 2 × t_{(1/2)}

∴ t = 2 × 15 = 30

\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2

\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75

∴ The amount left, N(t) = 0.75 grams

4 0
3 years ago
When would a cell use Active Transport? Mark all that apply.
Westkost [7]

Answer:

a c e

Explanation:

4 0
3 years ago
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