Kat owns 15% more figurines

Mathematics

1 answer:

Readme [11.4K]2 years ago

6 0

Answer:

Um what I would love to help but what is the question?

Step-by-step explanation:

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Please help me out here I'm failing math.

natulia [17]

Answer:

-4r - 11 = 4r + 21

-4r -4r = 21 + 11

-8 = 32 (Divide both sides by -8)

/ /

-8 -8

= -4

8 0

3 years ago

I need help with d 1 to d 3. I don't understand what to do.

erik [133]

What????

You just add 1 +3 =4

3 0

3 years ago

Rewrite in Polar Form.... x^(2)+y^(2)-6y-8=0

skad [1K]

$\bf x^2+y^2-6y-8=0\qquad 
\begin{cases}
x^2+y^2=r^2\\\\
y=rsin(\theta)
\end{cases}\implies r^2-6rsin(\theta)=8
\\\\\\
\textit{now, we do some grouping}\implies [r^2-6rsin(\theta)]=8
\\\\\\\
[r^2-6rsin(\theta)+\boxed{?}^2]=8\impliedby 
\begin{array}{llll}
\textit{so we need a value there to make}\\
\textit{a perfect square trinomial}
\end{array}$

$\bf 6rsin(\theta)\iff 2\cdot r\cdot \boxed{3\cdot sin(\theta)}\impliedby \textit{so there}
\\\\\\
\textit{now, bear in mind we're just borrowing from zero, 0}
\\\\
\textit{so if we add, \underline{whatever}, we also have to subtract \underline{whatever}}$

$\bf [r^2-6rsin(\theta)\underline{+[3sin(\theta)]^2}]\quad \underline{-[3sin(\theta)]^2}=8\\\\
\left. \qquad \right.\uparrow \\
\textit{so-called "completing the square"}
\\\\\\\
[r-3sin(\theta)]^2=8+[3sin(\theta)]^2\implies [r-3sin(\theta)]^2=8+9sin^2(\theta)
\\\\\\
r-3sin(\theta)=\sqrt{8+9sin^2(\theta)}\implies r=\sqrt{8+9sin^2(\theta)}+3sin(\theta)$

3 0

2 years ago

Help, please the question and thank you

lapo4ka [179]

The new triangle is gonna be bigger. But how big? Let’s look at A.
A= 2,8

Look at A’, it’s 6,24. See a pattern??
Multiply 2,8 by 3. It’s triple the amount, therefore the scale factor is 3.

To double check, multiply by 3 to B and C and see what you get.

4 0

2 years ago

Evaluate: |18| A:1/18 B:-1/-18 C:-18 D18

masya89 [10]

Answer will be D. Absolute value can never be negative.

4 0

2 years ago