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3 years ago

What type of electric current does a power plant generate for use in your home?

Physics

2 answers:

EastWind [94]3 years ago

9 0

B alternating, outlets have alternating currents that are supplied by power plants.
Hope this helps!

Naily [24]3 years ago

7 0

Answer : Alternating current.

Explanation :

We know that electric current is defined as the electric charge divided by time. There are two types of current i.e. direct current (D.C) and alternating current (A.C)

Direct current: The flow of electric charge in one direction is called as direct current. It was produced firstly by Alessandro Volta in 1800. One of the examples of direct current is the battery.

Alternating current: The flow of electric charges that reverses the direction periodically is known as alternating current.

Alternating current flows in our houses.

Hence, the correct option is(B) " Alternating current "

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What is the amount of thermal energy needed to make 5 kg of ice at - 10 °C to

agasfer [191]

Answer:

The amount of thermal energy needed is 15167500 joules.

Explanation:

By First Law of Thermodynamics, we see that amount of thermal energy ( $Q$ ), in joules, is equal to the change in internal energy. From statement we understand that change in internal energy consisting in two latent components ( $U_{l,ice}$ , $U_{l,steam}$ ), in joules, and two sensible component ( $U_{s,w}$ ), in joules, that is:

$Q = U_{l,ice} + U_{s, w} + U_{s,ice} + U_{l,steam}$ (1)

By definitions of Sensible and Latent Heat, we expanded the formula:

$Q = m\cdot (h_{f,w}+h_{v,w}+c_{ice}\cdot \Delta T_{ice}+c_{w}\cdot \Delta T_{w})$ (2)

Where:

$m$ - Mass, in kilograms.

$h_{f,w}$ - Latent heat of fussion of water, in joules per kilogram.

$h_{v,w}$ - Latent heat of vaporization of water, in joules per kilogram.

$c_{ice}$ - Specific heat of ice, in joules per kilogram per degree Celsius.

$c_{w}$ - Specific heat of water, in joules per kilogram per degree Celsius.

$\Delta T_{ice}$ - Change in temperature of ice, measured in degrees Celsius.

$\Delta T_{w}$ - Change in temperature of water, measured in degrees Celsius.

If we know that $m = 5\,kg$ , $h_{f,w} = 3.34\times 10^{5}\,\frac{J}{kg}$ , $h_{v,w} = 2.26\times 10^{6}\,\frac{J}{kg}$ , $c_{ice} = 2.090\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}$ , $c_{w} = 4.186\times 10^{3}\,\frac{J}{kg\cdot ^{\circ}C}$ , $\Delta T_{ice} = 10\,^{\circ}C$ and $\Delta T_{w} = 100\,^{\circ}C$ , then the amount of thermal energy is:

$Q = 15167500\,J$

The amount of thermal energy needed is 15167500 joules.

7 0

3 years ago

Define speed.

Vinvika [58]

The answer to the question is choice 2

7 0

3 years ago

Poorly treated municipal wastewater is discharged to a stream. The river flow rate upstream of the discharge point is Qu/s = 8.7

Musya8 [376]

Answer

given,

Q u = 8.7 m³/s

Q d= 0.9 m³/s

BOD concentration = 50 mg/L

a) BOD concentration at the down stream

$C_{down}=\dfrac{0.9\times 50}{8.7+0.9}$

$C_{down}=\dfrac{0.9\times 50}{9.6}$

= 4.69 mg/L

b) discharge = 9.6 m³/s

cross sectional area = 10 m²

velocity steam = $\dfrac{8.7+0.9}{10}$

= 0.96 m/s

time taken to move 50 km down stream = $\dfrac{50 \times 1000}{0.96}$

= 52083.3 s

= $\dfrac{52083.3}{3600\times 24}$

= 0.6 days

now,

$C_t=C_0e^{-kt}$

$C_t=4.6875\ e^{-0.2\times 0.6}$

$C_t = 4.16 mg/L$

5 0

4 years ago

The table represents a linear function. The rate of change between the points (–5, 10) and (–4, 5) is –5. What is the rate of ch

Digiron [165]

<span>8•5. Lesson 6. Lesson 6: Graphs of Linear Functions and Rate of Change ... in the table below: Input Output. 2. 5. 3.5. 8. 4. 9. 4.5. 10. ▫. The graph of a linear ... Yes, the rate of change betweeneach pair of inputs and outputs does seem to be .... The graph of the function will be a plot of fourpoints lying on a common line.</span><span>
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7 0

4 years ago

Read 2 more answers

A light bulb emitting 1750 Im of luminous flux shines on a book that is 3.0

denis-greek [22]

The illumination of the book is found to be approximately equal to 15 lx.

Option 1.

Explanation:

Luminous flux is the measure of power of the light emitted from a source and illumination is the property of the light to illuminate a given surface when it falls on the surface. So the measure of the region the light flux illuminates the surface is termed as illumination.

As here the luminous flux is given as 1759 lm and the distance of the object which has to be illuminated is placed 3 m away from the source ,the illumination is found to be directly proportional to the luminous flux and inversely proportional to the square of the distance between them

$illumination = \frac{Luminous flux}{4\pi d^{2} } \\\\illumination = \frac{1750}{4*3.14*3*3} = 15.48 lx = 15 lx$

So, the illumination of the book is found to be approximately equal to 15 lx.

5 0

3 years ago