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valentinak56 [21]
3 years ago
5

The table represents a linear function. The rate of change between the points (–5, 10) and (–4, 5) is –5. What is the rate of ch

ange between the points (–3, 0) and (–2, –5)?
Physics
2 answers:
Digiron [165]3 years ago
7 0
<span>8•5. Lesson 6. Lesson 6: Graphs of Linear Functions and Rate of Change ... in the table below: Input Output. 2. 5. 3.5. 8. 4. 9. 4.5. 10. ▫. The graph of a linear ... Yes, the rate of change betweeneach pair of inputs and outputs does seem to be .... The graph of the function will be a plot of fourpoints lying on a common line.</span><span>
</span>
NARA [144]3 years ago
3 0

Answer:

the anser is -5 hope you get a 100 on your test

Explanation:

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Which BEST describes the difference between speed and velocity?
kirill [66]

Answer : The correct option is, (D) Velocity includes rate of change and direction.

Explanation :

Speed : Speed is defined as the distance traveled by an object with respect to the time taken. It is a scalar quantity that means it tell us about the magnitude of an object not direction.

Velocity : Velocity is defined as the rate of change of position of an object with respect to the time. It is a vector quantity that means it tell us about the magnitude and direction of an object.

The only difference between the speed and the velocity is that the velocity tell us about magnitude and direction but speed tell us about magnitude only.

Hence, the correct option is, (D) Velocity includes rate of change and direction.


6 0
3 years ago
Read 2 more answers
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Ipatiy [6.2K]

Answer:

Explanation:

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3 0
3 years ago
Read 2 more answers
The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). W
FromTheMoon [43]

Answer:\alpha =30-4=26 rad/s^2

Explanation:

Given

Position of a car is  given by

\theta =t^3-2t^2-4t+10

and angular speed is \frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega

angular acceleration is

\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=\alpha

\alpha =6t-4

at t=5 s

\alpha =30-4=26 rad/s^2

4 0
4 years ago
Kinetic energy of an object is equal to
Gnom [1K]
See
K.E=1/2(mass*velocity²)
so option B is the correct answer.
Brainliest pls :-)
8 0
3 years ago
A bar magnet is dropped toward a conducting ring lying on the floor. As the magnet falls toward the ring, does it move as a free
Maslowich

Consider that the bar magnet has a magnetic field that is acting around it, which will imply that there is a change in the magnetic flux through the loop whenever it moves towards the conducting loop. This could be described as an induction of the electromotive Force in the circuit from Faraday's law.

In turn by Lenz's law, said electromotive force opposes the change in the magnetic flux of the circuit. Therefore, there is a force that opposes the movement of the bar magnet through the conductor loop. Therefore, the bar magnet does not suffer free fall motion.

The bar magnet does not move as a freely falling object.

3 0
3 years ago
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