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tensa zangetsu [6.8K]
3 years ago
9

Does the eruption in the video constitute a pyroclastic flow

Physics
1 answer:
densk [106]3 years ago
7 0

If it is the video I am thinking of then Yes


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Which of these is an example of a physical change? Question options: wood decaying iron melting paper burning steel rusting
marin [14]
Im pretty sure burning paper

its either that or melting iron but im 90 percent sure its paper burning
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3 years ago
True or false. A convection current is the circular motion of a fluid caused by the rising of heated fluid
xz_007 [3.2K]
True that is what a convection current is
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Linda is a forensic scientist arriving at the crime scene. What must she do before she can examine the crime scene?
Bezzdna [24]

Answer:

In the more scientific viewpoint, the most important thing that she must do is caring for her hygiene and put some plastic gloves in her hands.

This is because there are lots of particles that can be retained in the hands (dust, skin, etc), and when examining the scene, she may drop some of these particles, "contaminating" the scene in this way with information that only will affect the investigation.

So the most important thing is being prepared to not affect anything in the crime scene

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An object is made of glass and has the shape of a cube 0.13 m on a side, according to an observer at rest relative to it. Howeve
Vlad1618 [11]

Answer:

v=0.9833\ c

Explanation:

The density changes means that the length in the direction of the motion is changed.

Therefore,

$\text{Density} = \frac{m}{lwh}$

Given :

Side,  b = h = 0.13 m

Mass, m = 3.3 kg

Density = 8100 kg/m^3

So,

$8100=\frac{3.3}{l \times 0.13 \times 0.13}$

$l=\frac{3.3}{8100 \times 0.13 \times 0.13}$

l = 0.024 m

Then for relativistic length contraction,

$l= l' \sqrt{1-\frac{v^2}{c^2}}$

$0.024= 0.13 \sqrt{1-\frac{v^2}{c^2}}$

$0.184=  \sqrt{1-\frac{v^2}{c^2}}$

$0.033=  1-\frac{v^2}{c^2}}$

$\frac{v^2}{c^2}= 0.967$

$\frac{v}{c}=0.9833$

v=0.9833\ c

Therefore, the speed of the observer relative to the cube is 0.9833 c (in the units of c).

3 0
3 years ago
A 110 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.220 m/s. How much work must be d
Softa [21]

Answer:

the work that must be done to stop the hoop is 2.662 J

Explanation:

Given;

mass of the hoop, m = 110 kg

speed of the center mass, v = 0.22 m/s

The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;

W = ΔK.E

W = ¹/₂mv²

W = ¹/₂ x 110 x 0.22²

W = 2.662 J

Therefore, the work that must be done to stop the hoop is 2.662 J

6 0
3 years ago
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