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mixas84 [53]
3 years ago
5

The fastest growing plant on record is the Hesperoyucca whipplei. Suppose a plant of this type grows 3.7 m in 14 days. What is i

ts growth rate in micrometers per second?
Physics
1 answer:
swat323 years ago
8 0

Answer:

Growth rate in micrometers per second is 3.05.

Given:

Growing length = 3.7 meter

Time = 14 days

To find:

Growth rate = ?

Formula used:

Growth rate = \frac{Growing  length}{ time}

Solution:

Growth rate = \frac{Growing  length}{ time}

Growing  length = 3.7 × 10^{6} micrometer

Time = 14 × 24 × 60 × 60

Growth rate = \frac{3700000}{1209600}

Growth rate = 3.05 micrometer per second

Growth rate in micrometers per second is 3.05.


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Answer:

A

Explanation:

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Solid state has ____________ intermolecular force of attraction.
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A pulse traveled the length of a stretched spring the pulse transferred...A)energy only B)mass only C)both energy and mass D) ne
xz_007 [3.2K]

Answer:

A

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The magnitude of the electric field between two parallel charged plates is 200. An electron moves to the negative plate 5. 0 cm
Mama L [17]

The potential difference between the two ends of the circuit is the electric potential difference. The electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

<h3>What is an electric field?</h3>

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The given data in the problem is given by;

E is the electric field = (200 N/C)

d is the distance = 5.0 cm.=0.05 m

Q is the charge of electrons= 1.602 x 10^-19 C

The formula for electric potential  is given by;

\rm V=Ed

\rm V=Ed \\\\ \rm V=200 \times 0.05 \\\\ \rm V=  10 \frac{Nm}{C} = 10 \frac{J}{C}  = 10 V.

The work is defined as the product of the potential difference and charge of an electron.

\rm W= 10 \times  1.602 x 10^{-19} \\\\\ \rm W=  1.6 x 10^{-18 }J

Hence the electric potential difference and the work will be 10V and 1.6 x 10^-18 J respectively.

To learn more about the electric field refer to the link;

brainly.com/question/15071884

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3 years ago
How can a simple machine lift a heavy load with smaller effort​
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Answer:

The axle is fixed to a frame or a block. The pulley is normally fixed to a support above the load. The load is tied to one end of the rope and the effort is applied at the other end. Such a pulley makes our work easier by simply changing the direction of the force, i.e. a load is lifted up using a downward effort.

May be this will help U

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