Answer:

Explanation:
The motion of the tethered ball around the pole can be modeled as uniform circular motion. The acceleration of the objects executing uniform circular motion is due to the change in direction of their velocity. This is called centripetal acceleration. It is given by the following formula:

where,
ac = centripetal acceleration = ?
v = speed of ball = 3.5 m/s
r = distance of ball from center of rotation = 0.91 m
Using these values in equation, we get:

Answer:
c. remains the same, but the RPMs decrease.
Explanation:
Because there aren't external torques on the system composed by the person and the turntable it follows that total angular momentum (I) is conserved, that means the total angular momentum is a constant:

The total angular momentum is the sum of the individual angular momenta, in our case we should sum the angular momentum of the turntable and the angular momentum of a point mass respect the center of the turntable (the person)
(1)
The angular momentum of the turntable is:
(2)
with I the moment of inertia and ω the angular velocity.
The angular momentum of the person respects the center of the turntable is:
(3)
with r the position of the person respects the center of the turntable, m the mass of the person and v the linear velocity
Using the fact
:
(3)
By (3) and (2) on (1) and working only the magnitudes (it's all that we need for this problem):


Because the equality should be maintained, if we increase the distance between the person and the center of the turntable (r), the angular velocity should decrease to maintain the same constant value because I and m are constants, so the RPM's (unit of angular velocity) are going to decrease.
Answer: Chromium
Why Chromium has [Ar] 3d5 4s1 and Copper has [Ar] 3d10 4s1? Socratic.
Explanation:
Answer:
c
Explanation:
matter and energy van flow and cycle in an ecosystem depending on the temperature
Answer:
The total distance will be 400 m.
Explanation:
For portion AB:
Acceleration = 2
t= 10 s
Car start from rest , u=0 m/s
We know that


S= 100 m.
For portion BC:
V= u + at
V=0 + 2 x 10
V= 20 m/s
In this portion car moves with constant velocity 20 m/s for 10 s.
So distance S= V x t
S=20 x 10 =200 m.
For portion CD:
The velocity at point C will be 20 m/s
In this portion the final speed of car will be zero because given that at final car come to rest.
So the acceleration will be in the negative direction to stop the car.
We know that


S=100 m
The total distance AD=AB + BC+ CD
AD=100 +200 + 100 m
AD=400 m.
The total distance will be 400 m.