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DerKrebs [107]
2 years ago
5

Eating breakfast in the morning increases the ability to learn in school.

Physics
1 answer:
bonufazy [111]2 years ago
4 0

Answer:

Independent Variable - eating reakfast

Dependent Variable - ability to learn

Constant Variable - going to school

Explanation:

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A 40-w lightbulb connected to a 120-v source experiences a voltage surge that produces 132 v for a moment. by what percentage do
andrey2020 [161]
R=U^2/P=120*120/40=360 ohm
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2 years ago
The speed of an electromagnetic wave traveling in a transparent nonmagnetic substance is v = 1/ κμ0ε0 , where κ is the dielectri
vladimir1956 [14]

Answer:

v=2.24\times 10^{8}\ m/s

Explanation:

Given that,

The speed of an electromagnetic wave traveling in a transparent nonmagnetic substance is given by :

v=\dfrac{1}{\sqrt{k\mu_o\epsilon_o}}

Where

k is the dielectric constant of the substance.

v is the speed of light in water

c=\dfrac{1}{\sqrt{1.78\times 4\pi \times 10^{-7}\times 8.85\times 10^{-12}}}

v=2.24\times 10^{8}\ m/s

So, the speed of light in water is 2.24\times 10^{8}\ m/s

7 0
3 years ago
Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists d
galben [10]
Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists describe as elliptical. It is one of Kepler's laws. The sun is the focus of all the planets. The correct answer is D.
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Calculate the force of gravity between a comet with a mass of 500kg and a small asteroid with a mass of 20kg that is separated b
givi [52]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The equivalent gravitational force is ~

  • F  \approx1.48\times 10 {}^{ - 7}  \: \: N

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

We know that ~

\huge\boxed{\mathrm{F = \dfrac{ Gm_1m_2}{ r²}}}

where,

  • F = gravitational force

  • m_1 = mass of 1st object = 500 kg

  • m_2 = mass of 2nd object = 20kg

  • G = gravitational constant = 6.674 × {10}^ {-11}

  • r = distance between the objects = 2.12 m

Let's calculate the force ~

  • F = \dfrac{6.674   \times 10 {}^{ - 11} \times 500 \times 20}{(2.12) {}^{2} }

  • F = \dfrac{6.674  \times 10 {}^{ - 11} \times 10 {}^{4} }{4.4944}

  • F =  \dfrac{6.674}{4.4944}  \times 10 {}^{ - 7}

  • F =1.484 \times 10 {}^{ - 7}  \: \: newtons
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