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3 years ago

What is the least common multiple for 8 and 13

1 answer:

7 0

The Lcm is 104. The lcm of 13 and 8 is the smallest positive integer that divides the numbers 13 and 8 without a remainder. Spelled out, it is the least common multiple of 13 and 8. Here you can find the lcm of 13 and 8, along with a total of three methods for computing it. In addition, we have a calculator you should check out. Not only can it determine the lcm of 13 and 8, but also that of three or more integers including thirteen and eight for example. Keep reading to learn everything about the lcm (13,8) and the terms related to it.

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The local newspaper tells you that ad space costs 40 per column-inch. A "column-inchis space one column wide nch high. You want

mash [69]

Answer:

it should be 600

Step-by-step explanation:

40x3=120x5=600

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3 years ago

Indicate the formula for the following conditions. P(n,r)=

Oliga [24]

The formula is a permutation in which n represents the sample points in the set, while r represents the number of sample points in each permutation.

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3 years ago

Read 2 more answers

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

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3 years ago

Andrew has a cell phone plan that provides 300 free minutes each month for

Mekhanik [1.2K]

Answer:

Andrew has a cell phone plan that provides 300 free minutes each month for a flat rate of $19. For any minutes over 300, Andrew is charged $0.39 per minute. Let x be the number of minutes Andrew uses per month and f(x) be the charges based on Andrew's cell phone plan. If then If then first 300 minutes are free and each minute of next (x-300) minutes costs $0.39, therefore Hence, { 19 + 0.39(x - 300), x > 300

Hoped I helped

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3 years ago

Tickets to a play cost $14 each by mail, plus a $2 processing fee for each order or one or more tickets. Write a rule to describ

Aneli [31]

The equation would be 14x+2=t......

Breakdown: 14 times X (the number of tickets purchased) plus the one time processing fee of 2 dollars will equal T (the total)

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3 years ago