Answer:
k = 200 N/m
Explanation:
given,
mass of the object = 251 g
= 251 x 10⁻³ Kg = 0.251 Kg
distance of tendon stretch = x = 1.23 cm
= 1.23 x 10⁻² = 0.0123 m
using the formula
F = k x
where
k is the force constant of the tendon
F = m g
F = 0.251 x 9.8 = 2.4598 N
2.4598 = k x 0.0123
k = 199.98 N/m
k = 200 N/m
hence, force constant of the tendon is approximately equal to 200 N/m
It <span>states that the force F needed to extend or compress a spring by some distance X is proportional to that distance.
For elastic materials, they extend more in same amount of force, (as they are directly proportional), due to it's elastic nature (presence of large deforming force)
Hope this helps!</span>
The answer is C sorry if it’s wrong