All categories

3 years ago

Example of hallucinogens

Physics

2 answers:

podryga [215]3 years ago

5 0

LSD (lysergic acid diethylamide);

PCP (phencyclidine);

magic mushrooms (psilocybin);

ketamine;

mescaline (peyote cactus);

morning glory seeds;

datura.

Pani-rosa [81]3 years ago

5 0

Answer:

Explanation:

Hallucinogens are the mind altering drugs. These drugs changes the thinking, perception, consciousness and emotions. On consumption of these drugs can make things see, smell, hear and taste that are unrealistic. These can be categorized as psychedelics, which are the drugs responsible for changing the way how the human being perceives the world.

Examples of hallucinogens

LSD (lysergic acid diethylamide)

PCP (phencyclidine)

Datura

Psilocybin

Ketamine

Mescaline (peyote cactus)

You might be interested in

Jane has four glasses of milk. The temperature and the amount of milk in each glass are shown:

SOVA2 [1]

The molecules of milk in Glass B have greater kinetic energy than the molecules of milk in Glass D.

6 0

3 years ago

A conical container of radius 6 ft and height 24 ft is filled to a height of 19 ft of a liquid weighing 64.4 lb divided by ft cu

kobusy [5.1K]

Answer:

Part (i) work required to pump the contents to the rim is 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5ft above the cone's rim is 426,484.878 lb.ft

Explanation:

The center of mass of a uniform solid right circular cone of height h lies on the axis of symmetry at a distance of h/4 from the base and 3h/4 from the top.

Center mass of the liquid Z = (24-19)ft + 19/4 = 5ft + 4.75ft = 9.75 ft

Mass of liquid in the cone = volume × density (ρ) = ¹/₃.π.r².h.ρ

where;

r is the radius of the liquid surface = [6*(19/24)]ft = 4.75ft

ρ is the density of liquid = 64.4 lb/ft³

h is the height of the liquid = 19 ft

Mass of liquid in the cone = ¹/₃ × π × (4.75)² × 19 × 64.4 = 28,914.229 lbs

Part (i) work required to pump the contents to the rim

Work required = 28,914.229 lbs × 9.75 ft = 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5 ft above the cone's rim

Extra work required = 28,914.229 lb × 5ft = 144571.145 lb.ft

Total work required = (281,913.733 + 144571.145) lb.ft

= 426,484.878 lb.ft

5 0

3 years ago

I need help on my physics work and show me how you got it please

algol13

Answer

It increases to B, then it decreases.

When the stone thrown upwards, it moves vertically upwards to a maximum height then is starts to come down. Due to gravitational force, the velocity of the stone projected upwards decreases but when coming down wards is increases.

The trajectory shown in the diagrams represents an example of an object projected upwards.

We can then says that the vertical component increases from A to B, then it decreases to C.

4 0

4 years ago

A 1400 kg aircraft going 40 m/s collides with a 1500 kg aircraft that is parked and they stick together after the collision and

Leni [432]

Answer:

67.6 m

Explanation:

For this problem, we just need to analyze the motion of the two planes after the collision.

The two planes stick together and move with a velocity of

u = 19.3 m/s

The problem tells us that they skid until they stop: so, their final velocity is

v = 0

Since the velocity is not constant, this means that they are accelerating.

We also know that they skid for a time of

t = 7 s

Therefore, we can find their stopping distance using the following suvat equation

$s=(\frac{u+v}{2})t$

And substituting, we find

$s=(\frac{0+19.3}{2})(7)=67.6 m$

6 0

3 years ago

Check the correctness of formula t=2π √m/k, dimensionally

pantera1 [17]

Hi there! Lets see!

m is mass, and its units are kg
k is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²

Therefore:

$\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}} =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s$

The period is given in seconds so the formula is dimensionally correct.

4 0

3 years ago