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Bingel [31]
3 years ago
13

Crystal can ride her bike 10 miles in 2.1 hours. What is her velocity

Physics
1 answer:
masha68 [24]3 years ago
6 0

Answer:

v = 4.76 m/s

Explanation:

Given,

The distance traveled by her bike, d = 10 miles

The time of her travel, t = 2.1 m/s

The velocity of an object is defined as the distance traveled by the object to the time of travel. Therefore,

                          V = d/t   m/s

                              = 10 / 2.1

                              = 4.76 m/s

Hence, The velocity of her bike is, V = 4.76 m/s

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Can any one answer these two
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) (2.68 x 10¯5) x (4.40 x 10¯8)

The calculator display gives 1.1792 x 10¯12. Rounded off to three significant figures gives 1.18 x 10¯12 as the answer.

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The calculator display gives 4.2218 x 1019. Rounded off to three significant figures gives 4.22 x 1019 as the answer.

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The calculator display gives 1.2118 x 10¯9. Rounded off to three significant figures gives 1.21 x 10¯9 as the answer.

1) (2.68 x 10¯5) x (4.40 x 10¯8)

The calculator display gives 1.1792 x 10¯12. Rounded off to three significant figures gives 1.18 x 10¯12 as the answer.

2) (2.95 x 107) ÷ (6.28 x 1015)

The calculator display gives 4.6975 x 10¯9. Rounded off to three significant figures gives 4.70 x 10¯9 as the answer.

3) (8.41 x 106) x (5.02 x 1012)

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4) (9.21 x 10¯4) ÷ (7.60 x 105)

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3 years ago
76.8 kPa to mm of Hg
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Answer:

The answer is 576.0473

Explanation:

Hope this helps.

Please mark my answer as brainliest?

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have a nice day T_T

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3 years ago
A certain spring stretches 3 cm when a load of 15 n is suspended from it. how much will the spring stretch if 30 n is suspended
Alik [6]
Initially, the spring stretches by 3 cm under a force of 15 N. From these data, we can find the value of the spring constant, given by Hook's law:
k= \frac{F}{\Delta x}
where F is the force applied, and \Delta x is the stretch of the spring with respect to its equilibrium position. Using the data, we find
k= \frac{15 N}{3.0 cm}=5.0 N/cm

Now a force of 30 N is applied to the same spring, with constant k=5.0 N/cm. Using again Hook's law, we can find the new stretch of the spring:
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3 years ago
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