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2 years ago

Waves begin to "feel bottom" when the depth of water is

2 answers:

8 0

I think the correct answer would be one half the wavelength. Waves would "feel bottom" when the water is at the depth of 0.5 of the wavelength. "Feel bottom" is a term used to describe that the depth of water affects the wave properties. Hope this answers the question.

Likurg_2 [28]2 years ago

6 0

Equal to one-half the wavelength is the right answer.

Water is regulated by many approaches such as depth gauges (based on force) a sounding line and by sonar range. Prior to the modern era, sailors would cast metal weighted materials into the ocean. Submarines made a new demand for depth estimation, to need to know the depth of boats in the water. However, waves start to "feel bottom" when the depth of water is equivalent to one-half the wavelength. As the wave approaches a lightweight bank, its track is adjusted. This involution made the tides to become inactive. As the flow becomes steeper, the width of the wave diminishes.

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A suitcase (mass m = 18 kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures

Sindrei [870]

Answer:

P=2736 Pa

Explanation:

According to Newton we have that:

∑ $F=m*a\\$

A force is exerted by the elevator to the suitcase, according to 3th Newton's law an equal force but in the opposite direction will appeared on the suitcase, that is:

∑ $F=m*g+m*a=m*(g+a)$

$F=205.2N$

We know that the pressure is given by:

$P=\frac{F}{A}\\P=\frac{205.2N}{(0.50m)*(0.15m)}\\P=2736N/m^2=2736Pa$

6 0

3 years ago

A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu

Setler79 [48]

<h2>Given :</h2>

total charge = 9.0 mC = 0.009 C

Each electron has a charge of :

$1.6 \times 10 {}^{ - 19} \: C$

For producing 1 Cuolomb charge we need :

$\mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }$

$\dfrac{10 {}^{19} }{1.6}$

$\dfrac{10\times 10 {}^{19} }{16}$

$\dfrac{100 \times 10 {}^{18} }{16}$

$\mathrm{6.24 \times 10 {}^{18} \: \: electrons}$

Now, for producing 0.009 C of charge, the number of electrons required is :

$0.009 \times 6.24 \times {10}^{18}$

$0.05616 \times 10 {}^{18}$

$\mathrm{5.616 \times 10 {}^{16} \: \: electons}$

_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

$\mathrm{5.616 \times 10 {}^{16} \: \: electrons}$

Number of electrons passing through it in 1 Second is :

$\dfrac{5.616 \times {10}^{16} }{3.6}$

$\mathrm{1.56 \times 10 {}^{16} \: \: electrons}$

Now, in 10 seconds the number of electrons passing through it is :

$10 \times \mathrm{1.56 \times 10 {}^{16} \: \: }$

$\mathrm{1.56 \times 10 {}^{17} \: \: electrons}$

_____________________________

$\mathrm{ \#TeeNForeveR}$

6 0

2 years ago

Grizzly bears are known to run really fast. What is the momentum of a grizzly bear (about 420 pounds) running at 17 m/s ?

labwork [276]

Answer:

A. Momentum of the grizzly bear is 3241.56 Kgm/s

B. The human will run at 28.56 m/s

Explanation:

A. Determination of the momentum of the grizzly bear.

Mass of grizzly bear = 420 lb

Velocity of grizzly bear = 17 m/s

momentum of the grizzly bear =?

Next, we shall convert 420 lb to Kg. This can be obtained as follow:

1 lb = 0.454 kg

Therefore,

420 lb = 420 lb × 0.454 Kg / 1 lb

420 lb = 190.68 Kg

Thus, 420 lb is equivalent to 190.68 Kg

Finally, we shall determine the momentum of the grizzly bear as follow:

Mass of grizzly bear = 190.68 Kg

Velocity of grizzly bear = 17 m/s

momentum of the grizzly bear =?

Momentum = mass × velocity

Momentum = 190.68 × 17

Momentum = 3241.56 Kgm/s

Thus, the momentum of the grizzly bear is 3241.56 Kgm/s

B. Determination of how fast the human will run.

Mass of human = 250 lb

Momentum of human = momentum of the grizzly bear

Momentum of the grizzly bear is 3241.56 Kgm/s

Momentum of human = 3241.56 Kgm/s

Velocity of human =?

Next, we shall convert 250 lb to Kg. This can be obtained as follow:

1 lb = 0.454 kg

Therefore,

250 lb = 250 lb × 0.454 Kg / 1 lb

250 lb = 113.5 Kg

Thus, 250 lb is equivalent to 113.5 Kg

Finally, we shall determine how fast the human will run as follow:

Mass of human = 113.5 Kg

Momentum of human = 3241.56 Kgm/s

Velocity of human =?

Momentum = mass × velocity

3241.56 = 113.5 × velocity

Divide both side by 113.5

Velocity = 3241.56 / 113.5

Velocity = 28.56 m/s

Therefore, the human will run at 28.56 m/s to match the momentum of the grizzly bear

3 0

2 years ago

Which best describes what is made of matter?

a_sh-v [17]

Matter is made up of molecules and atoms

3 0

2 years ago

Read 2 more answers

A length of metal wire has a radius of 0.003 m and a resistance of 0.1 ω. when the potential difference across the wire is 16 v,

DENIUS [597]

By definition;
Vd = I/nQA

In which,
Vd = drift speed = 0.000282 m/s
I = current through the wire = V/R = 16/0.1 = 160 Amps
n = Density of free electrons
Q = Fundamental charge = 1.6*10^-19 C
A = Cross-sectional area of the wire = πr^2 =π*0.003^2 = 2.827*10^-5 m^2

Rearranging the expression for Vd above and substituting;
n = I/VdQA = 160/(0.000282*1.6*10^-19*2.827*10^-5) = 1.254*10^29 free electrons/m^3

8 0

3 years ago