His model was also called the Planetary model
Work=applied Force x distance
= 1275 x 26
=33150 Joules
Answer:
2,800 n
Explanation:
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Work needed: 720 J
Explanation:
The work needed to stretch a spring is equal to the elastic potential energy stored in the spring when it is stretched, which is given by

where
k is the spring constant
x is the stretching of the spring from the equilibrium position
In this problem, we have
E = 90 J (work done to stretch the spring)
x = 0.2 m (stretching)
Therefore, the spring constant is

Now we can find what is the work done to stretch the spring by an additional 0.4 m, that means to a total displacement of
x = 0.2 + 0.4 = 0.6 m
Substituting,

Therefore, the additional work needed is

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Linear momentum of a truck is 1,50,000 kg.m/s
Explanation:
Linear momentum is the product of the mass and velocity of an object. It is a vector quantity, which have a magnitude and a direction.
Linear momentum is a property of an object which is in motion with respect to a reference point (i.e. any object changing its position with respect to the reference point).
It's SI units are kg.m/s
Linear momentum is a vector quantity.
Linear momentum formula (p) = mass × velocity
Given data mass = 5000 kg ; velocity = 30 m/s
P = 5000 × 30
Linear momentum p= 1,50,000 kg.m/s