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Elodia [21]
3 years ago
7

What is the term for hardening or curing the sealant or composite material by exposing the material to a curing light?

Physics
1 answer:
natka813 [3]3 years ago
5 0

Answer:

Photopolymerization is the term for hardening or curing the sealant or composite material by exposing the material to a curing light

Explanation:

It the process through which a photopolymer reacts to the radiations in presence of the Ultra-violet light. Photopolymers refers to those materials and liquid or the plastic resins that are hardened in presence of light source such as the lasers or the lamps. When these materials are irradiated, they undergo chemical reactions and they are hardened and become solid, and hence the process called photopolymerization. Photopolymerization is majorly used in the coating and printing industries and in also in dentistry to fill the top of teeth and prevent the cavities

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To ensure a steady flight, the standard golf ball has nearly 400 ____ or “dimples” on its surface.
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PLEASE HELP ASAP 36. The Doppler Effect applies to light in addition to sound. What do you call the phenomenon that causes dista
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Answer:

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A projectile is fired at a velocity of 50 m/s straight into the air. What is the velocity of the projectile when the objects dis
Arisa [49]

Answer:

the final velocity of the object is 53.04 m/s.

Explanation:

Given;

initial velocity of the projectile, u = 50 m/s

displacement of the object, d = 16 m

let the final velocity of the object = v

Apply the following kinematic equation to determine the final velocity of the projectile.

v² = u² + 2gd

v² = 50² + (2 x 9.8 x 16)

v² = 2813.6

v = √2813.6

v = 53.04 m/s

Therefore, the final velocity of the object is 53.04 m/s.

8 0
3 years ago
a kid is flying a kite 58 meters above the level ground. a small lead sphere is dropped from the kite. calculate the amount of t
Fynjy0 [20]

This is the formula you need to memorize:  

D = 1/2 · a · T²

Distance = (1/2) · (acceleration) · (Time²)

This formula tells the distance an object falls in any amount of time.

This question tells you the distance (58m), and you know the acceleration (gravity, 9.8 m/s²), so you can use this formula to find the time.

Distance = (1/2) · (acceleration) · (Time²)

58m  =  (1/2) · (9.8 m/s²) · (Time²)

Divide each side by (4.9 m/s²) :  Time²  =  (58/4.9) seconds²

Take the square root of each side:  <em>Time = 3.44 seconds  </em>

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3 years ago
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