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Andrews [41]
4 years ago
14

Can you please help me

Mathematics
1 answer:
Paraphin [41]4 years ago
6 0

Answer:

7. The midpoint of the line segment AB is (2, 7/2) = (2, 3.5)

8. The slope of the line containing (6,3) and (4,-1) is 2

Step-by-step explanation:

7. A=(5,3)=(xa, ya)→xa=5, ya=3

B=(-1,4)=(xb, yb)→xb=-1, yb=4

Midpoint of the line segment AB: M=(xm, ym)=?

xm=(xa+xb)/2

xm=(5+(-1))/2

xm=(5-1)/2

xm=4/2

xm=2

ym=(ya+yb)/2

ym=(3+4)/4

ym=7/2

Midpoint of the line segment AB: M=(xm, ym)→M=(2, 7/2)=(2, 3.5)


8. Slope: m=?

P1=(6, 3)=(x1, y1)→x1=6, y1=3

P2=(4, -1)=(x2, y2)→x2=4, y2=-1

m=(y2-y1)/(x2-x1)

m=(-1-3)/(4-6)

m=(-4)/(-2)

m=2

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number of dimes + number of quarters = 30

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Also given that the coins total $ 4.80

number of dimes x  value of 1 dime + number of quarters x  value of 1 quarter = 4.80

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Let us solve eqn 1 and eqn 2

From eqn 1,

d = 30 - q ---- eqn 3

Substitute eqn 3 in eqn 2

0.1(30 - q) + 0.25q = 4.8

3 - 0.1q + 0.25q = 4.8

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d = 30 - 12

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Step-by-step explanation:

I'm a genius

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