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3 years ago

Question of the day.

Mathematics

1 answer:

matrenka [14]3 years ago

4 0

$\lambda = _0^{200}\sum (i)^f = 1+50(i-1-i+1) = 1 + 0i$
From this we know that $\lambda$ lies on the x-axis.
If z = 0, then k = $\lambda$ and point lies on curve L.

I believe the answer is C. It definitely not A or B.

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Match each slope and y-intercept with the appropriate linear equation

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240 divided by 10 = 24

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3 years ago

Rewrite the equation below in standard form.

eduard

Rewrite the equation below in standard form.
-3x+6y=12

C. -x+2y=4

if you take each term and divide them by 3 you will get the c

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3 years ago

The mean of the following data values is 32. <br> 19, 23, 35, 41, 42<br> A. True <br> B. False

wariber [46]

Answer:

False i think

Step-by-step explanation:

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3 years ago

According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h

andreyandreev [35.5K]

Answer:

The graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph $f(x)=x^2-4x+3$

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation $f(x)=x^2-4x+3$ the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, $f(x)=x^2-4x+3=0$

This is a quadratic equation, $x^2-4x+3=0$

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

$x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0$

$\Rightarrow x(x-1)-3(x-1)=0$

$\Rightarrow (x-3)(x-1)=0$

Using zero product property, $a\cdot b=0 \Rightarrow a=0\ or \ b=0$

$\Rightarrow (x-3)=0$ or $\Rightarrow (x-1)=0$

$\Rightarrow x=3$ or $\Rightarrow x=1$

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

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3 years ago