From the stoichiometry of the reaction, the percentage yiled of the copper is 89.6%
<h3>What is reaction equation?</h3>
The reaction equation here is given as; Fe(s) + CuSO4 (aq) ----->FeSO4(aq) + Cu(s)
Number of moles of Fe = 0.9845 g/56 g/mol = 0.018 moles. Since the reaction is 1:1, this is also the number of moles of Cu formed.
Theoretical yiled of Cu = 0.018 moles * 63.5 g/mol = 1.143 g
Percentage yiled = 1.024 g/1.143 g * 100/1 = 89.6%
If 1 mole of Fe contains 6.02 * 10^23 molecules
0.018 moles of Fe contains 0.018 moles * 6.02 * 10^23 molecules/1 mole = 1.1 * 10^22 molecules.
Number of moles of AgNO3 = 1.35 g/170 g/mol = 0.0079 moles
Molarity of the solution = 0.0079 moles/250 * 10^-3 L = 0.0032 M
Hence; 0.0032 M * V1 = 100 mL * 0.01 M
V1 = 312.5 mL
Learn more about stoichiometry: brainly.com/question/9743981
<span>Microscopic foreign particles that droplets form on is called the hygroscopic nuclei. The particles are already present in the air in the form of dust, salt from seawater evaporation and combustion residue. Together the particles begin the forming process of droplets.</span>
M(Na2CO3•10H2O)=23*2+12+16*3+180=286g/mol
So lets take 1 mol of this compound
m(comp)=286 gram
m(H2O)=180 gramm
w(h2o)=180/286=0.6293(62.93%)
Answer 62.93% water
Answer:
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