Answer:
you mean "jointed." jointed appendages give arthropods much greater movement flexibility and range.
Answer:
K2 = 9.701 x 10^-10
Explanation:
K1 = 4.0 x 10^-5
K2 = ?
T1 = -10.8 °C +273 = 262.2K
T2 = -16 °C + 273 = 257K
ΔHrxn = 120. kJ/mol = 120000 J/mol
The formular relating all these parameters is given as;
ln( K2 / K1) = −ΔHrxn / R * (1 / T2 − 1 / T1)
ln (K2 / 4.0 x 10^-5) = - 120000 / 8.314 (1 / 257 - 1 / 262.2)
ln (K2 / 4.0 x 10^-5) = 1.1138
ln K2 - ln4.0 x 10^-5 = 1.1138
ln K2 = 1.1138 + ln4.0 x 10^-5
ln K2 = 1.1138 - 10.1266
ln K2 = -9.0128
K2 = 9.701 x 10^-10
Answer is: the hydronium ion concentratio is 1.71×10⁻⁷ mol/dm³ and pH<6.76.
The Kw (the ionization constant of water) at 40°C is 2.94×10⁻¹⁴ mol²/dm⁶ or 2.94×10⁻¹⁴ M².
Kw = [H₃O⁺] · [OH⁻].
[H₃O⁺] = [OH⁻] = x.
Kw = x².
x = √Kw.
x = √2.94×10⁻¹⁴ M².
x = [H₃O⁺] = 1.71×10⁻⁷ M; concentration of hydronium ion.
pH = -log[H₃O⁺].
pH = -log(1.71×10⁻⁷ M).
pH = 6.76.
pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity an aqueous solution.
To solve this problem, we use the formula:
C1 V1 = C2 V2
where C is concentration and V is volume
15% * 1000 mL = 65% * V2
V2 = 230.77 mL
<span>So about 230.77 mL of 65% stock solution should be diluted
with water to 1000 mL to make 15% solution.</span>
The process of fusion or freezing