Answer:
(x - 8)(2x + 3)
Step-by-step explanation:
To factor a polynomial of the form
ax² + bx + c,
follow these steps:
1) Multiply ac together.
2) Find 2 factors of ac that add to b. Call these factors p and q.
3) Break up the middle term of the polynomial into px + qx.
4) Factor by grouping.
Now let's follow the steps above with your problem.
You are given the polynomial
2x² - 13x - 24,
so a = 2, b = -13, and c = -24
1) Find ac.ac is the product 2(-24) = -48
2) Now we need to find 2 factors of -48 that add to b, -13.
I know that 48 = 3 × 16, so if we use -16 and 3 for the two numbers, we have
-16 + 3 = -13
and -16 × 3 = -48.
3) Now we break up the middle term of the polynomial, -13x, into -16x + 3x.
The polynomial is now
2x² - 16x + 3x - 24
4) We factor the polynomial by grouping. To factor by grouping, you factor a common factor out of the first 2 terms and factor out a common factor out of the last two terms.
2x² - 16x + 3x - 24 =
= 2x(x - 8) + 3(x - 8)
We now see the common factor of x - 8, so we factor that out.
= (x - 8)(2x + 3)
Answer: (x - 8)(2x + 3)
Answer:
x= 2
x= -3
Step-by-step explanation:
<u>Solving as normal quadratic equation:</u>
- 2x^2+2x=12
- x^2 +x = 6
- x^2 + x - 6= 0
- x = (-1 ± √(1+4*1*6)/2
- x = ( - 1 ± √25)/2
- x = (-1 ± 5)/2
- x= 2
- x= -3
<u>Roots are</u> 2 and -3
Since x co-ordinates are constant, answer has to be difference in y co ordinates therefore the answer is 4
Answer: 290951.87
Step-by-step explanation:
Hope this helps :D
