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SVETLANKA909090 [29]
3 years ago
13

How to find the value of x in complementary angles?

Mathematics
1 answer:
strojnjashka [21]3 years ago
5 0
Since complements of the same angle are congruent, we know that both angles are congruent, meaning they have the same measure. To find the value of X, set the two angles equal to each other and solve
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Otrada [13]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
This isn't middle school it's 4th grade. what is the LCM of 9, 15?​
vagabundo [1.1K]

Answer:

LCM of 9 and 15 is 45.

Step-by-step explanation:

What is the LCM of 9 and 15?

Find the prime factorization of 9.

Find the prime factorization of 15. 15 = 3 × 5.

Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM: LCM = 3 × 3 × 5.

LCM = 45.

(hope this helps can i plz have brainlist :D hehe)

7 0
2 years ago
Read 2 more answers
The point (5, -1) is a solution of the equation: y = 2x − 11 question 28 options: true false
kkurt [141]
True
This is because on replacing for x=5;
y=2x-11
y=2(5)-11
y=10-11
y=-1

8 0
3 years ago
Trapezoid ABCD is congruent to trapezoid . Which sequence of transformations could have been used to transform trapezoid ABCD to
dedylja [7]
The answer is D: Trapezoid ABCD was reflected across the y-axis and then rotated 90° counterclockwise around the origin
4 0
3 years ago
A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu
Mars2501 [29]

Answer:

There can be at most 12 attendees in a corporate team-building event.

Step-by-step explanation:

Let x denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

8 0
3 years ago
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