Answer:
Step-by-step explanation:
1) Determine the GCF of the numbers 96 and 88
=> Decompose each number in their prime numbers:
=> 96 = (2^5)(3)
=> 88 = (2^3) (11)
=> GCF of 96 and 88 = 2^3 = 8
2) Determine the GCF of the letters, x^2 and x
=> x
3) Conclude the GCF of the terms is 8x
4) Now you can factor the expression by dividing each term by the GCF, 8x:
96 x^2 / (8x) = 12x
88x / (8x) = 11
The factored form is (8x) (12x + 11)
B! 27 please mark brainliest
-1, .5, 2
I don’t see a 4th dot
1. The midpoint of the segment joining points (a, b) and ( j, k) is ((j+a)/2,(k+b)/2)
2. Let the coordinate of H be (a, b)
T(0, 4) = ((a + 0)/2, (b + 2)/2)
(a + 0)/2 = 0 => a + 0 = 0 => a = 0
(b + 2)/2 = 4 => b + 2 = (2 x 4) = 8 => b = 8 - 2 = 6
Therefore, the cordinate of H is (0, 6)
3. Point (-4, 3) lies in Quadrant II
4. Point (6, 0) lies on the x-axis
5. Any line with no slope is parallel to the y-axis
7. a is the value of the x-coordinate.
5a + 3 = 8
5a = 8 - 3 = 5
a = 5/5 = 1
a = 1
8. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => a = -5 and b = 7.
Therefore, its center point is (-5, 7)
9. Equation of a circle is given by (x - a)^2 + (y - b)^2 = r^2; where (a, b) is the center and r is the radius.
For the given circle (x + 5)^2 + (y - 7)^2 = 36 => (x - (-5))^2 + (y - 7)^2 = 6^2 => r = 6.
Therefore, its radius is 6
10. If the equation of a circle is (x - 2)^2 + (y - 6)^2 = 4, the center is point (2, 6).
True
6x^2 - 37x + 22
Use the FOIL method to multiply the binomials.
First monomial in each binomial: 3x * 2x = 6x^2
Outside monomials: 3x * -11 = -33x
Inside monomials: -2 * 2x = -4x
Last monomial in each binomial: -2 * -11 = 22
Now, just add: 6x^2 - 33x - 4x + 22 = 6x^2 - 37x + 22