Which equation is the result of solving y-p=m(x-q) for x

Mathematics

1 answer:

pickupchik [31]3 years ago

4 0

Answer:

x= y/m-p/m-q ; m≠0

Step-by-step explanation:

y-p= m(x-q)

Divide both sides by m

y/m -p/m= x-q

add q to y/m - p/m

x= y/m- p/m +q

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Determine whether the two expressions are equivalent. Explain your reasoning.

dlinn [17]

Let us evaluate each pair of expressions one at a time.
8. (n²+4) - n² and 4n.
(n²+4) - n² = n²+ 4 - n² = 4 which is not equal to 4n.
NOT EQUIVALENT

9. 3x + 5 and 2(x + 3)
2(x + 3) = 2x + 6 which is not equal to 3x + 5.
NOT EQUIVALENT

10. 15 - 6x and 15(1 - 6x)
15(1 - 6x) = 15 - 90x which is not equal to 15 - 6x
NOT EQUVALENT

11. (y + y + 2 + y) + 3y and 6y + 2
(y +y +2 + y) + 3y = y+y+y +2 + 3y = 3y + 2 + 3y = 6y + 2.
It matches the other expression.
EQUIVALENT

12. 8y - 3 + 10y and 3(6 - 1)
8y - 3 + 10y = 8y + 10y - 3 = 18y - 3
3(6 - 1) = 3(5) = 15
The two expressions do not match.
NOT EQUIVALENT.

Answer: Only the expressions in number 11 are equivalent.

6 0

3 years ago

What integer values satisfy both inequalities? − 2 < x < 3 − 2 ≤ x < 2

NARA [144]

Given:

The inequalities are:

$-2$

$-2\leq x$

To find:

The integer values that satisfy both inequalities.

Solution:

We have,

$-2$

$-2\leq x$

For $-2$ , the possible integer values are

$x=-1,0,1,2$ ...(i)

For $-2\leq x$ , the possible integer values are

$x=-2,-1,0,1$ ...(ii)

The common values of x in (i) and (ii) are

$x=-1,0,1$

Therefore, the integer values -1, 0 and 1 satisfy both inequalities.

6 0

2 years ago

Help please Draw an obtuse angle (labeled BIG) Place a point P inside the angle. Now construct perpendiculars form the point to

Mice21 [21]

Answer:

The side closest to P is the side that is on the same side of the angle bisector as P.

Step-by-step explanation:

The angle bisector is the line containing all the points equidistant from the sides of the angle. Points on one side of the angle bisector are closer to the angle side that is on that side of the angle bisector.

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The attached diagram shows the angle bisector as a dashed line. A couple of different locations for P are shown (P1 and P2). Apparently, we're concerned here with the distance from P along the perpendicular to each side of the angle. For P2 (on the left side of the angle bisector), it may be clear that the left perpendicular is shorter than the right one. Likewise, for P1, the right perpendicular will be shorter.