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3 years ago

Find the volume of a cylinder with a diameter of 8 inches and a height that is three times radius

Mathematics

2 answers:

ollegr [7]3 years ago

6 0

Answer:

96π^2 = 947.48

Step-by-step explanation:

π × r² × h

8π times 3*4*π

Gnesinka [82]3 years ago

4 0

Answer: 603 cubic inches

Step-by-step explanation:

Let's find radius (r):

Diameter is double the radius, so the radius is 4 inches.

Let's find the height (h):

Height is 3 times the radius so the height is 12 inches.

Now let's find the volume:

V = πr^2 × h

V = π × 16 × 12

V = 603 cubic inches

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2 years ago

Which of the following pairs of functions are inverses of each other?

natta225 [31]

Answer:

The pair which are inverse of each other are:

Option: C

$f(x)=11x-4\ and\ g(x)=\dfrac{x+4}{11}$

Step-by-step explanation:

Two functions f(x) and g(x) are said to be inverse of each other if:

fog(x)=gof(x)=x

i.e. the composition of two functions give identity no matter what the order is.

$f(x)=\dfrac{x}{12}+15$ and $g(x)=12x-15$

Now we calculate fog(x):

$fog(x)=f(g(x))\\\\fog(x)=f(12x-15)\\\\fog(x)=\dfrac{12x-15}{12}+15\\\\fog(x)=x-\dfrac{15}{12}+15\\\\fog(x)=x-\dfrac{55}{4}\neq x$

Hence, option: A is incorrect.

$f(x)=\dfrac{3}{x}-10\ and\ g(x)=\dfrac{x+10}{2}$

Now we calculate fog(x):

$fog(x)=f(g(x))\\\\fog(x)=f(\dfrac{x+10}{3})\\\\fog(x)=\dfrac{3}{\dfrac{x+10}{3}}-10\\\\fog(x)=\dfrac{9}{x+10}-10\neq x$

Hence, option: B is incorrect.

$f(x)=9+\sqrt[3]{x}\ and\ g(x)=9-x^3$

Now we calculate fog(x):

$fog(x)=f(g(x))\\\\fog(x)=f(9-x^3)$

$fog(x)=9+\sqrt[3]{9-x^3}\neq x$

Hence, option: D is incorrect.

$f(x)=11x-4\ and\ g(x)=\dfrac{x+4}{11}$

Now we calculate fog(x):

$fog(x)=f(g(x))\\\\fog(x)=f(\dfrac{x+4}{11})$

$fog(x)=11\times (\dfrac{x+4}{11})-4\\\\fog(x)=x+4-4\\\\fog(x)=x$

Similarly,

$gof(x)=g(f(x))\\\\gof(x)=g(11x-4)\\\\gof(x)=\dfrac{11x-4+4}{11}\\\\gof(x)=\dfrac{11x}{11}\\\\gof(x)=x$

Hence, option: C is the correct option.

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2 years ago

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