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2 years ago

Can you solve this for me

Mathematics

1 answer:

jenyasd209 [6]2 years ago

4 0

The number in the blank box should be 44 because it said that "3 times x and 4 times y is 44".

You need to multiply the first equation by 3:

3x + 3y = 39.

Then, subtract the first equation from the second equation:

3x - 3x = 0

4y - 3y = y

44 - 39 = 5

Your new equation should look like this: y = 5

Now, substitute y = 5 into the first original equation:

x + 5 = 13

x = 8

Ans. (x, y) = (8, 5)

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How to convert a repeating decimal to a fraction

egoroff_w [7]

Always place it out of 9. For example, 0.333= 3/9, or if simplified, 1/3.

0.5555? this will be 5/9.

for the other way around, make it a repeating decimal, such as 4/9, make that 0.444

If it is 33/99, or even 333/999, the rule should be the same.

8 0

3 years ago

Find the area of a parallelogram with the given vertices. P(-2, -5), Q(9, -5), R(1, 5), S(12, 5)

valentina_108 [34]

Answer:

The area of the parallelogram is 55 square unit.

Step-by-step explanation:

The area of a parallelogram is

$A=\frac{1}{2}\times base\times height$

It is given that the vertices of the parallelogram are P(-2, -5), Q(9, -5), R(1, 5), S(12, 5).

Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.

From the graph is clear that length of PQ is 11 and the height of the parallelogram is 10. So, the area of a parallelogram is

$A=\frac{1}{2}\times 11\times 10$

$A=55$

Therefore the area of the parallelogram is 55 square unit.

4 0

2 years ago

How to simplify 40/100

777dan777 [17]

Answer:

40/100=4/10=2/5 2/5 is the simplest form

7 0

2 years ago

Help me find my answer

Sergeu [11.5K]

Step-by-step explanation:

3 cookies= 240 cal

∴ 1 cookie= 240÷3 cal

∴ 5 cookies= (240÷3) × 5

⇒ 240÷3= 80

⇒ 80 × 5= 400

[ans] 400 cal

4 0

3 years ago

Find the range. 3 –9 7 –1 5 –4 2

grin007 [14]

Put in order from smallest to largest
–9, –4, –1, 2, 3, 5, 7

Minimum = –9<span>
Maximum = 7

</span>Range = 7 - (-9) = 7 + 9 = 16

Range = the difference between the maximum and minimum data values

hope it helps

7 0

3 years ago