Answer:
The entropy change of the Universe that occurs is 19.346 J/K
Explanation:
Given;
temperature of the sun, 
= 5,300 K
temperature of the Earth, 
= 293 K
radiation energy transferred by the sun to the earth, E = 6000 J
The sun loses Q of heat and therefore decreases its entropy by the amount
The earth gains Q of heat and therefore increases its entropy by the amount
The total entropy change is:
Therefore, the entropy change of the Universe that occurs is 19.346 J/K
Answer:
98 m √
Explanation:
How about s = Vo * t + ½at² ?
s = h = Vo * 2s - 4.9m/s² * (2s)² = 2Vo - 19.6
and
h = Vo * 10s - 4.9m/s² * (10s)² = 10Vo - 490
Subtract 2nd from first:
0 = -8Vo + 470.4
Vo = 58.8 m/s
h = 58.8m/s * 2s - 4.9m/s² * (2s)² = 98 m
Answer:
The value is 
Explanation:
From the question we are told that
The initial speed is 
at a distance of 
The final speed is 
at a distance of 
Generally from the kinematic equation we have that
=> 
=> 
=>
The negative sign shows that it is decelerating
