347÷134=2.589552239 meters per second
2.589552239×60= 155.3731343 meters per hour
155.3731343 meters per hour= 0.096544389701642 miles per hour
hopefully this was right.
Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?
Liquid is the answer
We use the Rydberg Equation for this which is expressed as:
<span>1/ lambda = R [ 1/(n2)^2 - 1/(n1)^2]
</span>
where lambda is the wavelength, where n represents the final and initial states. Brackett series means that the initial orbit that electron was there is 4 and R is equal to 1.0979x10^7m<span>. Thus,
</span>
1/ lambda = R [ 1/(n2)^2 - 1/(n1)^2]
1/1.0979x10^7m = 1.0979x10^7m [ 1/(n2)^2 - 1/(4)^2]
Solving for n2, we obtain n=1.
The reactants are always on the left side of the reaction. The hydrogen peroxide: H2O2
reactants --> products
Umm... I think I saw this question somewhere else answered.... You should look for it.
