Consider the following function.
1 answer:
We have that
<span>f(x) = (3/2)*x + 4
case 1) for x=-8
</span>f(-8) = (3/2)*(-8) + 4--------> -8
point (-8,-8)
case 2) for x=-4
f(-4) = (3/2)*(-4) + 4--------> -2
point (-4,-2)
case 3) for x=-2
f(-2) = (3/2)*(-2) + 4--------> 1
point (-2,1)
case 4) for x=0
f(0) = (3/2)*(0) + 4--------> 4
point (0,4)
case 5) for x=2
f(2) = (3/2)*(2) + 4--------> 7
point (2,7)
case 6) for x=4
f(4) = (3/2)*(4) + 4--------> 10
point (4,10)
using a graph tool
see the attached figure
<span>f(x) = (3/2)*x + 4
case 1) for x=-8
</span>f(-8) = (3/2)*(-8) + 4--------> -8
point (-8,-8)
case 2) for x=-4
f(-4) = (3/2)*(-4) + 4--------> -2
point (-4,-2)
case 3) for x=-2
f(-2) = (3/2)*(-2) + 4--------> 1
point (-2,1)
case 4) for x=0
f(0) = (3/2)*(0) + 4--------> 4
point (0,4)
case 5) for x=2
f(2) = (3/2)*(2) + 4--------> 7
point (2,7)
case 6) for x=4
f(4) = (3/2)*(4) + 4--------> 10
point (4,10)
using a graph tool
see the attached figure
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Answer:
Part A; Initial dosage is 10 milligrams
Part B:
8.4113 milligrams after 1 hour
5.0057 milligrams after 4 hours.
Step-by-step explanation:
It is given M(h)= 10
Initial dosage is the 10 milligrams
After 1 hour, plug in h as 1
So, M(1)=10
Simplify the right side
M(1)=10(0.84113)
M(1)= 8.4113 milligrams.
Now, after 4 hours
M(4)=10
M(4)=10(0.50057)
M(4) =5.0057 milligrams