Answer: The Lewis structure of Chloroacetate can be found at the attachment below.
Explanation:
CH2ClCOO- The chemical compound is called Chloroacetate.
Reference link for the Chloroacetate structure.
https://www.google.com/search?q=lewis+structure+for+CH2ClCOO-&prmd=ivn&sxsrf=ALeKk03mQcLiY-q5pEriMR0_26ZTXLjmJg:1589680325594&source=lnms&tbm=isch&sa=X&ved=2ahUKEwjfxPPY5LnpAhVloXEKHeAwD-wQ_AUoAXoECA4QAQ&cshid=1589680746615&biw=360&bih=559&dpr=3#
Answer:
We need 17.2 L of Ca(OH)2
Explanation:
Step 1: Data given
Concentration of Ca(OH)2 = 1.45 M
Moles of H2SO4 = 25.0 moles
Step 2: The balanced equation
Ca(OH)2 + H2SO4 ⟶2H2O + CaSO4
Step 3: Calculate moles Ca(OH)2
For 1 mol Ca(OH)2 we need 1 mol H2SO4 to produce 2 moles H2O and 1 mol CaSO4
For 25.0 moles H2SO4 we'll need 25.0 moles Ca(OH)2 to produce 50 moles H2O and 25.0 moles CaSO4
Step 4: Calculate volume of Ca(OH)2
Volume Ca(OH)2 = moles Ca(OH)2 / concentration Ca(OH)2
Volume Ca(OH)2 = 25.0 moles / 1.45 M
Volume Ca(OH)2 = 17.2 L
We need 17.2 L of Ca(OH)2
Answer:
B) any complex thing with properties normally associated with living things
Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.
<h3>What is volume?</h3>
Volume is the area occupied by the substance and is the ratio of the mass to the density.
At STP, 1 mole of gas occupies 22.4 L of volume
Given,
Volume of ammonia reacted = 0.720 L
The combustion reaction is shown as,

From the stoichiometry of the reaction, it can be said that,
L of ammonia reacts with
L of oxygen gas.
So, 0.720 L of ammonia will react with:

Therefore, the volume of oxygen required is 900 mL.
Learn more about volume here:
brainly.com/question/14090111
#SPJ4