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ahrayia [7]
3 years ago
6

When iron forms an ion with a plus three charge, the formula of a compound with iron (Fe3+) and sulfur (S) is Fe2S3, right?

Chemistry
2 answers:
LekaFEV [45]3 years ago
6 0

Answer: Yes the formula of the compound formed is Fe_2S_3

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

If iron is having an oxidation state of +3 called as Fe^{3+} cation. Sulphur is an anion with oxidation state of -2 and forms sulphide ion S^{2-}. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Fe_2S_3.

The cations and anions being oppositely charged attract each other through strong coloumbic forces and form an ionic bond.

Setler79 [48]3 years ago
4 0
Yes

2Fe(3+) + 3S(2-) ----> Fe2S3

:-) ;-)
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How are the following aspects of a reaction affected by the addition of a catalyst? 1) activation energy of the reverse reaction
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These are four questions and four answers.

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1) activation energy of the reverse reaction

     b. Decreased

2) Rate of the forward reaction

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4) Activation energy of the forward reaction

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Explanation:

<em>Activarion energy</em> is the energy required by the reactants to form the intermediate transition state and become products.

<em>Catalysts</em> are substances that change the path of the chemical reactions, lowering the activation energy, and thus speeding up the rate of the reactions, since the products can reach the new lower activation energy faster.

The equilibrium reactions are the chemical process in which two reactions, the <em>forward and the reverese reactions</em>, occur simultaneously and at the same rate.  The equlibrium reactions may be represented by:

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Where A → B is the direct or forward reaction, and A ← B is the reverse reaction (note the inversed arrow, from right to left).

For the direct reaction A represents the reactants and B represents the products. On the other hand, B represents the reactants and A represents the reactants of the reverse reaction and A. This, is A is the reactant of the forward reaction and the product of the reverse reaction, while B is the reactant of the reverse reaction and the product of the forward reaction.

Since, <em>the addition of a catalyst</em> lowers the activation energy of the process, the new activation energy is lower for both the forward and the reverse reaction, meaning that:

1. <em>The activation energy of the reverse reaction is decreased</em> (option b. of the first question)

2.<em> The rate of the forward reaction is increased</em> (option a. of the second question)

3. <em>The rate of the reverse reaction is increased</em> (option a. of the third question).

4. <em>Activation energy of the forward reaction is decreased</em> (option b. of the fourth question).

In summary, the addition of a catalyst decreases the activation energy for both forward and reverse reactions, and increases the rate of both forward and reverse reactions.

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