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BARSIC [14]
4 years ago
9

I need help with this :/

Chemistry
1 answer:
uranmaximum [27]4 years ago
6 0
Ok please tell me what exactly you need help with

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How many ml of cranberry juice is required to prepare a 25 ml 12% cranberry solution using a 20% cranberry stock solution?
Zolol [24]
To answer this question, you need to equalize the content of the cranberry for both solutions. The content could be count by multiplying the percentage with the volume of the cranberry juice. Then the calculation would be:

content1= content2
concentration1 * volume1= concentration2 * volume2
12%* 25 ml  = 20%* volume2
volume2= 25ml * 12%/ 20%= 15ml
7 0
4 years ago
How many neutrons does Argon 41 have ​
skelet666 [1.2K]
The number of neutrons is 22
3 0
3 years ago
Read 2 more answers
Gold (111) Chloride
ZanzabumX [31]

Answer:

Explanation:

Gold (111) Chloride:

AuCl₃

The oxidation state of gold is +3.

Chlorine is present in group seventeen and have seven valance electrons . Thus it accept one electron to complete the octet and show oxidation state -1.

When it react with gold(III) three chlorine atoms are combine with one gold atom to make compound overall neutral.

Calcium Carbonate:

CaCO₃

Carbonate formula is CO₃²⁻ . It means it carry -2 charge . Calcium is present in group two. It has two valance electrons and lose them to get complete octet thus shows +2 oxidation state.

When it combine with carbonate the overall compound is neutral because -2 and +2 charges cancel each other.

Hydrobromic Acid

HBr

Hydrogen has one electron while bromine has seven valance electrons. Bromine require one more electron to complete the octet. It react with hydrogen by sharing of one electron of hydrogen and form polar covalent compound.

4 0
3 years ago
Calculate the molar solubility of pbi2 in the presence of 0.10 m nai.
lys-0071 [83]

The equation representing the solubility of PbI_{2}:

PbI_{2}(aq)Pb^{2+}(aq) + 2 I^{-}(aq)

5 0
3 years ago
Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.
N76 [4]

Answer:

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

V

i

​

=22.4dm

3

V

f

​

=?

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

V

i

​

V

f

​

​

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

V

i

​

V

f

​

​

)

⇒1000=−1×2.303×2×273×log(

22.4

V

f

​

​

)

Explanation:

6 0
3 years ago
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