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Assoli18 [71]
3 years ago
9

Which description matches the graph of the inequality y ≥ |x + 2| – 3? a shaded region above a solid boundary line a shaded regi

on below a solid boundary line a shaded region below a dashed boundary line a shaded region above a dashed boundary line

Mathematics
1 answer:
Alex777 [14]3 years ago
6 0
The given inequality is y ≥ |x + 2| -3.

This inequality may be written two ways:
(a) y ≥ x + 2 - 3
    or
    y ≥ x - 1

(b) y ≥ -x -2 - 3
    or
     y ≥ -x - 5

A graph of the inequality is shown below. The shaded region satisfies the inequality.

Answer: A shaded region above a solid boundary line.

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10. What is the value of the function f(x) = 7x when x = 0.75 ?
melomori [17]

Answer:

7(0.75) = 5.25

f = 7

Step-by-step explanation:

7 0
2 years ago
What dose this symbol ∠ mean?
AURORKA [14]

Answer:

it either means angle or less than. pretty sure it means angle tho, cos less than is like this <

Ste. p-by-step explanation:

3 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Crm%5Csum_%7Bn%20%3D%201%7D%5E%20%5Cinfty%20%28%20-%201%20%7B%29%7D%5E%7Bn%20-%201%7D%
victus00 [196]

Let

\displaystyle f(x) = \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n-1}}{(2n-1)! (2n+1)}

The exponent is indeed 2n-1 - not a typo!

Take the antiderivative of f, denoted by F. This recovers a factor of 2n in the denominator, which lets us condense it to a single factorial.

\displaystyle F(x) = \int f(x) \, dx = C + \sum_{n=1}^\infty (-1)^{n-1} \frac{x^{2n}}{(2n+1)!}

Recall the series expansion of sine,

\displaystyle \sin(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!}

Then with a little algebraic manipulation, we get

\displaystyle F(x) = \int f(x) \, dx = C + 1 - \frac{\sin(x)}x

Differentiate to recover f.

f(x) = \dfrac{\sin(x) - x\cos(x)}{x^2}

Finally, f(\pi) = \frac1\pi, so our sum is

\displaystyle \pi^2 f(\pi) = \sum_{n=1}^\infty (-1)^{n-1} \frac{\pi^{2n+1}}{(2n-1)! (2n+1)} = \boxed{\pi}

3 0
1 year ago
Jacob needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.
dalvyx [7]

An inequality that represent  the number of cans, c, that Jacob must still collect is  c\geq 56 .

<u>Step-by-step explanation:</u>

Here we have , Jacob needs to collect at least 120 cans for a food drive to earn community service credit. He has already collected 64 items.  We need to solve the following :

<u>Part A: </u>

Write and solve an inequality to represent the number of cans, c, that Jacob must still collect.

Jacob has collected 64 cans . Jacob need to collect at least 120 cans for a food drive to earn community service credit , Let Number of cans that Jacob have to collect is c , So following is the inequality for above scenario:

⇒ c+64\geq 120

⇒ (c+64)-64\geq 120-64

⇒ c\geq 56

Therefore , An inequality that represent  the number of cans, c, that Jacob must still collect is  c\geq 56 .

8 0
3 years ago
The cost of a school banquet is $80 plus $12 for
schepotkina [342]

Answer:

80+12(83)=c

c=1076

Step-by-step explanation:

12 * 83= 996

996+80=1076

c=1076

7 0
3 years ago
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