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3 years ago

15

The scale on a map of Virginia shows that 1 inch represents 20 miles the actual distance from Richmond Virginia to Washington DC

is 110 miles on the map how many inches are between the two cities

1 answer:

DedPeter [7]3 years ago

7 0

Answer:

5.5 inches

Step-by-step explanation:

Proportions:

1 inch ⇔ 20 miles

W inch ⇔ 110 miles

W = 110*1/20

W = 5,5 inch

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Solve for H: A = L ⋅ W ⋅ H

Sergeu [11.5K]

Answer:

The answer would be

H = A over L times W

Step-by-step explanation:

This is because, when you multiply the L, W, and H you end up getting A. This means that A is the biggest number. We automatically can tell that H is what were looking for so putting those two things together we have this: H = A over ???

The ??? would have to be L times W because those are the only things left and they get multiplied together which in the end leaves us with

H = A over L times w

aka

H=A/LxW

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What is 48 divide by 2

ddd [48]

Answer:

48 dived by 2 =24

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If the sum of three consecutive numbers is 36. Find the numbers.

aleksandrvk [35]

Answer:

11, 12, 13

Step-by-step explanation:

x is the first number

(x + 1) is the second number

(x + 2) is the third number

x + x+1 + x+2 = 36

3x + 3 = 36

3x = 36 - 3

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x = 11 ← the first number

the second number = x + 1 = 11 + 1 = 12

the third number = x + 2 = 11 + 2 = 13

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3 years ago

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Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

<u>Algebra I</u>

Terms/Coefficients

Expanding/Factoring

<u>Calculus</u>

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

<u>Step 2: Differentiate</u>

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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2 years ago

What are x and 8 in this lineat equation? 8/x+5=50/25

MatroZZZ [7]

Answer:

x= -8/3

Step-by-step explanation:

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3 years ago