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3 years ago

What number is needed to finish the pattern 66 73 13 21 52 _ 10 20

2 answers:

5 0

I think the answer is 61 because :
If you split the six numbers into little groups :
66 + 7 = 73
13 + 8 = 21
52 + 9 = 61
10 + 10 = 20
You see the pattern is add one more too each group
Therefore, the answer is 61
:)

Nuetrik [128]3 years ago

4 0

I think that the answer is 61 I got this off of google so I'm not 100 percent sure please don't take my word as anything but second advice.

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Fred had 108!dollars to spend on 6 books after buying them he had 18 dollars how much did each book cost?

lana [24]

Each book costs $15. since he had 18 dollars left, you can subtract 18 from 108. then divide that answer by 6. 90/6 = 15.
Hope that helped!

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2 years ago

A rectangular swimming pool has an area of (70x + 10) square feet. Find possible dimensions of the pool.

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Answer:

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3 years ago

how many ounces of a 24% alcohol solution and a 29% alcohol solution must be combined to obtain 90 ounces of a 25% solution

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Step-by-step explanation:

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3 years ago

a temperature of -6° is colder than a temperature of 5°f below zero . is this statement true or false ?

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3 years ago

A cash box contains $74 made up of quarters, half-dollars, and one-dollar

Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

$0.25q+0.50h+1.00d=74$

$\displaystyle{h=\frac{3}{5}d+1}$

$q=4(d+h)$

Then, substitute q in the first equation with the expression from the third equation:

$0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74$

Next, substitute h in that equation with the expression from the second equation:

$\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}$

$2d+0.9d+1.5=74\\2.9d+1.5=74$

Solve for d, the number of one-dollar coins:

$2.9d+1.5=74\\2.9d=72.5\\d=25$

Substitute 25 for d in the second equation to find h, the number of half-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{h=\frac{3}{5}(25)+1}$

$h=15+1\\h=16$

Substitute 25 for d and 16 for h in the third equation to find q, the number of quarters:

$q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164$

Then, verify that the coins total $74:

$0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}$

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

$\displaystyle{h=\frac{3}{5}d+1}$

$\displaystyle{16=\frac{3}{5}(25)+1}$

$16 = 15 + 1\\16 = 16\\\text{Check.}$

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

$q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}$

6 0

3 years ago