The answer is b. False because radiation transfers energy by the propagation of waves within the electromagnetic spectrum and the travel of photons. Therefore, no matter is moved within this process.
D) How fast you are moving
Answer:
19÷5 time equals speed upon distance so 950÷250 will give 19/5 hours
The given statement "An AED should only be used if a person is too tired to continue with chest compressions" is false.
Answer: Option B
<u>Explanation:</u>
Most people think that they are very tired after applying the compress for 2-3 minutes. When the compressor is tired, it tends to compress more slowly. For this reason, rescuers are advised to do compressions in every 2 min to prevent fatigue and optimise the compressions quality. This should only be done if the person does not show signs of life or is dead, does not respond and breathes normally.
For example, consider you come across the victim in a narrow place and you have two helpers: Rescuer 2 arrives with the AED (automated external defibrillator) and puts it on the opposite side from Rescuer 1, who does chest compressions. Rescuer 2 turns on the AED and fixes the electrodes to the victim's chest, connecting wires to the AED if necessary. Rescuer 1 can continue CPR (Cardiopulmonary resuscitation) by placing electrodes until the victim's heart rate has been analysed.
Answer:
The shearing stress is 10208.3333 Pa
The shearing strain is 0.25
The shear modulus is 40833.3332 Pa
Explanation:
Given:
Block of gelatin of 120 mm x 120 mm by 40 mm
F = force = 49 N
Displacement = 10 mm
Questions: Find the shear modulus, Sm = ?, shearing stress, Ss = ?, shearing strain, SS = ?
The shearing stress is defined as the force applied to the block over the projected area, first, it is necessary to calculate the area:
A = 40*120 = 4800 mm² = 0.0048 m²
The shearing stress:
![Ss=\frac{F}{A} =\frac{49}{0.0048} =10208.3333Pa](https://tex.z-dn.net/?f=Ss%3D%5Cfrac%7BF%7D%7BA%7D%20%3D%5Cfrac%7B49%7D%7B0.0048%7D%20%3D10208.3333Pa)
The shearing strain is defined as the tangent of the displacement that the block over its length:
![SS=tan\theta =\frac{Displacement}{L} =\frac{10}{40} =0.25](https://tex.z-dn.net/?f=SS%3Dtan%5Ctheta%20%3D%5Cfrac%7BDisplacement%7D%7BL%7D%20%20%3D%5Cfrac%7B10%7D%7B40%7D%20%3D0.25)
Finally, the shear modulus is the division of the shearing stress over the shearing strain:
![Sm=\frac{10208.3333}{0.25} =40833.3332Pa](https://tex.z-dn.net/?f=Sm%3D%5Cfrac%7B10208.3333%7D%7B0.25%7D%20%3D40833.3332Pa)