What happen when a hurricane crosses over land

A girl stands on the edge of a merry-go-round of radius 1.71 m. If the merry go round uniformly accerlerates from rest to 20 rpm

Mashutka [201]

Answer:

$a = 0.53 m/s^2$

Explanation:

initially the merry go round is at rest

after 6.73 s the merry go round will accelerates to 20 rpm

so final angular speed is given as

$\omega = 2\pi f$

$\omega = 2\pi ( \frac{20}{60})$

$\omega = 2.10 rad/s$

so final tangential speed is given as

$v = r\omega$

$v = 1.71 (2.10) = 3.58 m/s$

now average acceleration of the girl is given as

$a = \frac{v_f - v_i}{\Delta t}$

$a = \frac{3.58 - 0}{6.73}$

$a = 0.53 m/s^2$

8 0

3 years ago

The Solar System is made up of eight planets, numerous comets, asteroids, and moons, and the Sun. The force that holds all of th

Nastasia [14]

Answer:

B. GRAVITY is the answer

7 0

3 years ago

Read 2 more answers

Compare and contrast instantaneous and average speed.

Harlamova29_29 [7]

Answer:

instantaneous velocity is a velocity covered at an instant while average velocity is the change in distance/ the change in time taken

6 0

3 years ago

An amusement park ride consists of a rotating circular platform 8.26 m in diameter from which 10 kg seats are suspended at the e

VashaNatasha [74]

To solve this problem we will begin by finding the necessary and effective distances that act as components of the centripetal and gravity Forces. Later using the same relationships we will find the speed of the body. The second part of the problem will use the equations previously found to find the tension.

PART A) We will begin by finding the two net distances.

$r = \frac{8.26}{2} = 4.13m$

And the distance 'd' is

$d = lsin\theta$

$d = 1.14 sin 16.2\°$

$d = 0.318m$

Through the free-body diagram the tension components are given by

$Tcos\theta = mg$

$Tsin\theta = \frac{mv^2}{R}$

Here we can watch that,

$R = r+d$

Dividing both expression we have that,

$tan\theta = \frac{v^2}{Rg}$

Replacing the values,

$tan(16.2) = \frac{v^2}{(4.13+0.318)(9.8)}$

$v = 4.83371m/s$

PART B) Using the vertical component we can find the tension,

$Tcos\theta = mg$

$T = \frac{mg}{cos\theta}$

$T = \frac{(10+26.2)(9.8)}{cos(16.2)}$

$T = 369.42N$

6 0

3 years ago

Which form of energy does a plant store when light is transformed during photosynthesis into sugars?

AlexFokin [52]

Answer:

C. Chemical energy

Explanation:

The different types of energy listed in this question are:

A) Electrical energy: it is the energy related to the flow of electrical charges (current)

B) Nuclear energy: it is the energy contained in the nuclei of the atoms, and released during nuclear reactions

C) Chemical energy: it is the energy contained in the bonds between molecules, and it is released during chemical reactions

D) Thermal energy: it is the energy associated with the motion of molecules

Photosynthesis is the process that plants use to transform the light energy (coming from the Sun) into chemical energy. In fact, in this process, plants absorb CO2 (from the atmosphere) and solar energy (from the light), and they convert them into sugars (glucose) and oxygen. Therefore, the initial energy coming as solar energy is converted into energy of the bonds of the molecules of glucose (so, chemical energy).

So, the correct option is C).

4 0

3 years ago