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2 years ago

How is fabric made from fur different from fabric made of hair?

Physics

1 answer:

Dmitry [639]2 years ago

3 0

Answer:

The principal hair fiber used to produce textile fabrics is sheep's wool. In wild sheep, the wool is a short, soft underlayer protected by longer, coarser hair. ... Fur fibers from animals such as mink and beavers are sometimes blended with other hairs to spin luxury yarns but are most often found as fur pelts.

You might be interested in

Which statement is true regarding coppers ability to conduct electricity

Alecsey [184]

Copper is the second best known electrical conducting substance. The first best one is silver. We almost always use copper because silver costs too much.

6 0

3 years ago

Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to

Deffense [45]

Answer:

P2 = 128,205 pascal.

Explanation:

Given the following data;

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

$PT = K$

Where;

P represents pressure.

T represents temperature.

K is the constant of proportionality.

$\frac{P1}{T1} = \frac{P2}{T2}$

Making P2 as the subject formula, we have;

$P_{2}= \frac{P1}{T1} * T_{2}$

Substituting into the equation, we have;

$P_{2}= \frac{100000}{273} * 350$

$P_{2}= 366.3004* 350$

P2 = 128205.13 ≈ 128205 pascal.

Therefore, the pressure inside the hot water bottle is 128,205 pascal.

5 0

2 years ago

A 0.5 kg yellow bouncy ball rolls to the right at a speed of 8 m/s while a 0.25 kg blue bouncy ball rolls

inessss [21]

Explanation:

Let yellow ball be m1 = 0.5kg with u1 = 8 m/s and blue ball be m2 = 0.25 kg with u2 = - 4 m /s respectively.

After collision, blue ball travels 12 m/s.

Using conservation of Linear Momentum :

m1u1 + m2u2 = m1v1 + m2v2

0.5* 8 + 0.25 * - 4 = 0.5 * v1 + 0.25 * 12

v1 = 0 m/sec i.e. Yellow ball comes to rest.

3 0

3 years ago

A spring is attached to the ceiling and pulled 8 cm down from equilibrium and released. The amplitude decreases by 17% each seco

Vadim26 [7]

Answer:

D(t) = 8(0.83)^(t) cos 38πt

Explanation:

We are told that the spring oscillates 19 times each second.

Thus, period = 1/19

We are also told that it's pulled 8cm downwards and the amplitude decreases by 17% each second.

Thus;

Amplitude;A = 8 × (1 - (17/100))^(t)

A = 8(0.83)^(t)

If we consider the function;

y = A cos (bx - c) + d

Now, 2π/b = period

So, 1/19 = 2π/b

b = 38π

So, D(t) = 8(0.83)^(t) cos (38πt - c) + d

Since we started from minimum,

Vertical shift, d = 0 and horizontal shift c = 0

So,we now have;

D(t) = 8(0.83)^(t) cos 38πt

3 0

3 years ago

The longest pipe on a certain organ is 5.34 m. (a) what is the frequency f3 (at 0.00°c) if the pipe is closed at one end?

-Dominant- [34]

For a pipe open at both ends, fund frequency (Fo) given byFo = v /2L

v = velocity of sound = 340 m/s (at about 20ºC)

Fo = 340/2*5.34 = 31.8 Hz

While for the one closed at one end and open at the other end...

For a pipe open at one end, fund frequency (Fo) given byFo = v/4L

Fo = 340/4*5.34= 15.9 Hz

7 0

3 years ago